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Calculating the integral of a function of the form $\\frac{mx^2+nx+k}{(x+a)(x+b)(x+c)}$ using partial fractions.

", "licence": "None specified"}, "statement": "

Calculate the integral

\n

\\[ \\simplify{int(({m}x^2+{n}x+{k})/((x+{a})(x+{b})(x+{c})),x)}. \\]

", "advice": "

In order to integrate the function \\[ \\simplify{({m}x^2+{n}x+{k})/((x+{a})(x+{b})(x+{c}))}, \\]we want to rewrite it in terms of its partial fractions. 

\n

To do this, we want to set the function equal to the sum of 3 fractions with denominators $\\simplify{x+{a}}$, $\\simplify{x+{b}}$, and $\\simplify{x+{c}}$. Since these are all distinct linear factors, this tells us that the numerators will be constants, which we will call $A$, $B$, and $C$:

\n

\\[ \\simplify{({m}x^2+{n}x+{k})/((x+{a})(x+{b})(x+{c}))} = \\simplify{A/(x+{a}) + B/(x+{b})+ C/(x+{c})}.\\]

\n

To find the values of $A$, $B$, and $C$, we want to first multiply this equation by the denominator of the left-hand side. This gives

\n

\\[ \\simplify{{m}x^2+{n}x+{k}=A(x+{b})(x+{c})+B(x+{a})(x+{c}) + C(x+{a})(x+{b})}.\\]

\n

\n

To find $A$, we can eliminate $B$ and $C$ by setting $x=\\var{-a}$:

\n

\\[ \\simplify{{m*a^2-n*a+k}=A{(b-a)(c-a)}} \\implies A=\\simplify[fractionNumbers]{{Asol}}.\\]

\n

Finding $B$ by setting $x=\\var{-b}$:

\n

\\[ \\simplify{{m*b^2-n*b+k}=B{(a-b)(c-b)}} \\implies B=\\simplify[fractionNumbers]{{Bsol}}.\\]

\n

Finally, setting $x=\\var{-c}$ we can find C:

\n

\\[ \\simplify{{m*c^2-n*c+k}=C{(a-c)(b-c)}} \\implies C=\\simplify[fractionNumbers]{{Csol}}.\\]

\n

Therefore,

\n

{check}

\n

Hence,

\n

\\[ \\begin{split} \\simplify{int(({m}x^2{n}x+{k})/((x+{a})(x+{b})(x+{c})),x)} &\\,=  \\simplify[all,fractionNumbers]{int({m*a^2-n*a+k}/({(b-a)*(c-a)}(x+{a}))+{m*b^2-n*b+k}/({(a-b)*(c-b)}(x+{b}))+{m*c^2-n*c+k}/({(a-c)*(b-c)}(x+{c})),x)}\\\\ \\\\ &\\,=\\simplify[basic,fractionNumbers,zeroTerm,unitFactor,noLeadingMinus]{{Asol} int(1/(x+{a}),x)+{Bsol} int(1/(x+{b}),x)+{Csol} int(1/(x+{c}),x)}   \\\\\\\\ &\\,=\\simplify[basic,fractionNumbers,zeroTerm,unitFactor,noLeadingMinus]{{Asol} ln (abs(x+{a}))+{Bsol} ln (abs(x+{b}))+{Csol} ln (abs(x+{c})) + C}. \\end{split}\\]

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\\\\[ \\\\simplify{({m}x^2+{n}x+{k})/((x+{a})(x+{b})(x+{c}))} = \\\\simplify{{Asol}/(x+{a})+{Bsol}/(x+{b})+{Csol}/(x+{c})}.\\\\]

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\\\\[ \\\\simplify{({n}x+{k})/((x+{a})(x+{b})(x+{c}))} = \\\\simplify[all,fractionNumbers]{{m*a^2-n*a+k}/({(a-b)(a-c)}(x+{a}))+{m*b^2-n*b+k}/({(b-a)(b-c)}(x+{b}))+{m*c^2-n*c+k}/({(c-a)(c-b)}(x+{c}))} .\\\\]

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