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Multiple choice question. Given a randomised polynomial select the possible ways of writing the domain of the function.

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Det er gitt en funksjon

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The function $\\simplify{{out}}$ is a piecewise function. It is defined on different parts (or pieces) of its domain by different (sub)functions.

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In particular, the pieces of the domain are the intervals

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and their corresponding (sub)functions are given by the expressions

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In the case of the function $\\simplify{{out}}$ above, each of the (sub)functions are defined for the indicated intervals and so the domain of $\\simplify{{out}}$ are all of those intervals combined. The first and second interval join nicely without a gap unlike the rest and so we have \\[\\text{dom}(\\simplify{{out}})=\\{\\simplify{{inp}}\\in\\mathbb{R}:\\, \\simplify{{inp}}\\leq \\var{b1},\\; \\var{b2}\\leq \\simplify{{inp}}<\\var{b3},\\; \\var{b3}<\\simplify{{inp}}\\leq\\var{b4}, \\text{ or }\\; \\simplify{{inp}}\\ge \\var{b5}\\}.\\]

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$\\simplify{{out}}(\\simplify{{inp}})=\\left\\{\\begin{align}&\\simplify{{p0}},&& \\text{ for } \\simplify{{inp}}< \\var{b0}, \\\\&\\simplify{{p1}},&& \\text{ for } \\var{b0}\\leq \\simplify{{inp}}\\leq \\var{b1},\\\\ &\\simplify{{p2}},&& \\text{ for } \\var{b2}\\leq\\simplify{{inp}}< \\var{b3},\\\\ &\\simplify{{p3}},&& \\text{ for } \\var{b3}<\\simplify{{inp}}\\leq \\var{b4},\\\\ &\\simplify{{p4}},&& \\text{ for } \\simplify{{inp}}\\ge\\var{b5}.\\end{align}\\right.$

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Hvilke av følgende mengdene er definisjonsmegden til $\\simplify{{out}}(\\simplify{{inp}})$?

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$\\text{D}_\\simplify{{out}}=\\mathbb{R}$

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$\\text{D}_\\simplify{{out}}=\\{\\simplify{{inp}}\\in\\mathbb{R}:\\, \\simplify{{inp}}\\leq \\var{b1},\\; \\var{b2}\\leq \\simplify{{inp}}\\leq\\var{b4}, \\text{ or }\\; \\simplify{{inp}}\\ge \\var{b5}\\}$

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$\\text{D}_\\simplify{{out}}=\\{\\simplify{{inp}}\\in\\mathbb{R}:\\, \\simplify{{inp}}\\leq \\var{b1},\\; \\var{b2}\\leq \\simplify{{inp}}<\\var{b3},\\; \\var{b3}<\\simplify{{inp}}\\leq\\var{b4}, \\text{ or }\\; \\simplify{{inp}}\\ge \\var{b5}\\}$

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$\\text{D}_\\simplify{{out}}=\\{\\simplify{{inp}}\\in\\mathbb{R}:\\, \\simplify{{inp}}< \\var{b0},\\; \\var{b2}\\leq \\simplify{{inp}}<\\var{b3},\\; \\var{b3}<\\simplify{{inp}}\\leq\\var{b4}, \\text{ or }\\; \\simplify{{inp}}\\ge \\var{b5}\\}$

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$\\text{D}_\\simplify{{out}}=\\{\\simplify{{inp}}\\in\\mathbb{R}:\\, \\simplify{{inp}}< \\var{b1},\\; \\var{b2}< \\simplify{{inp}}\\leq\\var{b3},\\; \\var{b3}\\leq\\simplify{{inp}}<\\var{b4}, \\text{ or }\\; \\simplify{{inp}}> \\var{b5}\\}$

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$\\text{D}_\\simplify{{out}}=\\mathbb{R}^5$

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$\\text{D}_\\simplify{{out}}=\\{\\simplify{{inp}}\\in\\mathbb{R}:\\, \\simplify{{inp}}< \\var{b0},\\; \\var{b0}< \\simplify{{inp}}<\\var{b1},\\;\\var{b2}\\leq \\simplify{{inp}}<\\var{b3},\\; \\var{b3}<\\simplify{{inp}}\\leq\\var{b4}, \\text{ or }\\; \\simplify{{inp}}\\ge \\var{b5}\\}$

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