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A worked example using the equation from Part a:
\n$\\simplify{{f1}x^2+{f2}*x+{f3}}=0$
\nFirstly, start to find the possible common factors of the coefficient of $x$ (here, $\\var{f2}$), and the constant ($\\var{f3}$).
\nHere there are some possible factors of $\\var{f3}$, but we need to find two numbers which will sum to make $\\var{f2}$ (since the coefficient of $x^2$ is $1$ in this case).
\nWe can use $\\var{c}$ and $\\var{d}$, since
\n$\\var{c}*\\var{d}=\\var{f3}$
\nand
\n$\\var{c}+\\var{d}=\\var{f2}$.
\nOnce you have found the two numbers which will work, put them into two brackets like so:
\n$\\simplify{(x+{c})(x+{d})}$
\nThis is your simplification.
\n\n\n\n\nIf you wanted to find the solutions for $x$, you would take each bracket and equate it to zero.
\nSome students may find this hard to see instantly, so the method is explained below.
\nTaking the first bracketed term,
\n($\\simplify{x+{c}}$)
\nand equating it to $0$
\n$\\simplify{x+{c}}=0$
\nthen gives us a very simple equation.
\nFrom this, we can see $x=\\simplify{0-{c}}$.
\nThe same goes for the second bracket:
\n$x=\\simplify{0-{d}}$.
\n\n\n\nA similar technique is used when the coefficient of $x^2$ is not $1$.
\nIt simply must be taken into account that the factors will be multiplied by this.
\nFor example, taking the equation $2x^2+7x+5$:
\nThe only factors of $5$ are $5$ and $1$.
\nCreating the empty brackets,
\n$($$2x+$ $)($$x+$ $)$
\nwe can see that they must be filled as follows:
\n$(2x+5)(x+1)$
\nas multiplying this out gives the original equation.
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\n$=$[[0]]
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\n$=$[[0]]
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\n$=$[[0]]
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", "showStrings": true, "strings": ["^"], "partialCredit": "0"}, "vsetrangepoints": 5, "expectedvariablenames": ["x"], "checkingaccuracy": 0.001, "vsetrange": [0, 1], "showpreview": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "showCorrectAnswer": true, "answersimplification": "all", "scripts": {}, "answer": "({a3}x+{c3})({b3}x+{d3})", "marks": "2", "checkvariablenames": true, "checkingtype": "reldiff", "type": "jme"}], "showCorrectAnswer": true, "scripts": {}, "marks": 0, "type": "gapfill"}], "statement": "Simplify the following quadratics into two linear factors of the form $(ax+c)(bx+d)$.
\nRemember, the constants in your expression can be positive or negative.
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