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A worked example using the equation from Part a:

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$\\simplify{{f1}x^2+{f2}*x+{f3}}=0$

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Firstly, start to find the possible common factors of the coefficient of $x$ (here, $\\var{f2}$), and the constant ($\\var{f3}$).

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Here there are some possible factors of $\\var{f3}$, but we need to find two numbers which will sum to make $\\var{f2}$ (since the coefficient of $x^2$ is $1$ in this case).

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We can use $\\var{c}$ and $\\var{d}$, since

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$\\var{c}*\\var{d}=\\var{f3}$

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and

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$\\var{c}+\\var{d}=\\var{f2}$.

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Once you have found the two numbers which will work, put them into two brackets like so:

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$\\simplify{(x+{c})(x+{d})}$

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This is your simplification.

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If you wanted to find the solutions for $x$, you would take each bracket and equate it to zero.

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Some students may find this hard to see instantly, so the method is explained below.

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Taking the first bracketed term,

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($\\simplify{x+{c}}$)

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and equating it to $0$

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$\\simplify{x+{c}}=0$

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then gives us a very simple equation.

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From this, we can see $x=\\simplify{0-{c}}$.

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The same goes for the second bracket:

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$x=\\simplify{0-{d}}$.

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A similar technique is used when the coefficient of $x^2$ is not $1$.

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It simply must be taken into account that the factors will be multiplied by this.

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For example, taking the equation $2x^2+7x+5$:

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The only factors of $5$ are $5$ and $1$.

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Creating the empty brackets,

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$($$2x+$    $)($$x+$    $)$

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we can see that they must be filled as follows:

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$(2x+5)(x+1)$

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as multiplying this out gives the original equation.

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$\\simplify{{f1}x^2+{f2}*x+{f3}}$

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$=$[[0]] 

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The answer must be factorised.

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Hint: try to find two numbers which will sum to the $x$ coefficient and multiply to the constant integer.

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$\\simplify{{f12}x^2+{f22}*x+{f32}}$

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$=$[[0]] 

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The answer must be factorised.

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$\\simplify{{f13}x^2+{f23}*x+{f33}}$

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$=$[[0]] 

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The answer must be factorised.

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Simplify the following quadratics into two linear factors of the form $(ax+c)(bx+d)$.

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Remember, the constants in your expression can be positive or negative.

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Factorising basic quadratics into linear expressions

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