// Numbas version: exam_results_page_options {"name": "Generelle derivasjonsregler", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "Generelle derivasjonsregler", "tags": [], "metadata": {"description": "", "licence": "All rights reserved"}, "statement": "

Deriver funksjonene under.

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Merk: For å skrive inn f.eks. $\\frac{1}{x^3}$ bør man skrive 1/(x^3), for å skrive inn $\\cos^2x$ bør man skrive (cos(x))^2. Bruk * når det skal være et produkt mellom to bokstaver.

", "advice": "

Bruk følgende generelle derivasjonsregler

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$f(x)=a\\cdot u(x)$ gir $f'(x)=a\\cdot u'(x)$ ($a$ er et konstant)

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$f(x)=u(x)+v(x)$ gir $f'(x)=u'(x)+v'(x)$ 

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$f(x)=u(x)-v(x)$ gir $f'(x)=u'(x)-v'(x)$ 

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$f(x)=u(x)\\cdot v(x)$ gir $f'(x)=u'(x)\\cdot v(x)+u(x)\\cdot v'(x)$  (produktregelen)

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$f(x)=\\dfrac{u(x)}{v(x)}$ gir $f'(x)=\\dfrac{u'(x)\\cdot v(x)-u(x)\\cdot v'(x)}{v^2(x)}$ (brøkregelen)

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$f(x)=g(u(x))$ gir $f'(x)=g'(u(x))\\cdot u'(x)$ (kjerneregelen)

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$\\simplify{{out1}}(\\simplify{{inp1}})=\\simplify{{k1}*sin({inp1})-{k2-1}*{inp1}^{{a}}+1/{inp1}}$

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$\\simplify{{out1}}'(\\simplify{{inp1}})=$ [[0]]

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$\\simplify{{out2}}(\\simplify{{inp2}})=\\var{inp2}^{\\var{k2}}\\cdot\\ln \\var{inp2}+\\var{k3+5}$

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$\\simplify{{out2}}'(\\simplify{{inp2}})=$ [[0]]

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$\\simplify{{out3}}(\\simplify{{inp3}})=\\var{k3}^\\var{inp3}\\cos(\\var{inp3})$

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$\\simplify{{out3}}'(\\simplify{{inp3}})=$ [[0]]

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$\\simplify{{out4}}(\\simplify{{inp4}})=\\dfrac{\\cos(\\var{inp4})}{\\sin(\\var{inp4})}$

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$\\simplify{{out4}}'(\\simplify{{inp4}})=$ [[0]]

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$\\simplify{{out5}}(\\simplify{{inp5}})=\\dfrac{\\var{inp5}^{\\var{k5}}}{\\var{inp5}^{\\var{k2-3}}+\\var{inp5}^{\\var{k1-1}}}$

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$\\simplify{{out5}}'(\\simplify{{inp5}})=$ [[0]]

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$\\simplify{{out6}}(\\simplify{{inp6}})=(\\simplify{{inp6}^{{k6}}+{inp6}+{k7}})(\\simplify{{inp6}^{{k7-2}}+{inp6}})$

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$\\simplify{{out6}}'(\\simplify{{inp6}})=$ [[0]]

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$\\simplify{{out7}}(\\simplify{{inp7}})=(\\var{k2}+\\var{inp7}^{\\var{k4}})^{\\var{k6}}$

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$\\simplify{{out7}}'(\\simplify{{inp7}})=$ [[0]]

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$\\simplify{{out8}}(\\simplify{{inp8}})=\\cos(\\simplify{{inp8}^{{k8}}+{inp8}+{k1}})$

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$\\simplify{{out8}}'(\\simplify{{inp8}})=$ [[0]]

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