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Målet i denne oppgaven er å finne god tilnærming til $\\sqrt{\\var{k^2+1}}$.

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La oss sette en funksjon $f(x)=\\sqrt{x}$

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Linearisering til $f(x)$ i punkt $x=x_0+\\Delta x$ er gitt ved

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$F(x)\\approx f'(x_0)(x-x_0)+f(x_0)$.

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Da linearisering til $f(x)=\\sqrt{x}$ i punkt $\\var{k^2+1}$ er gitt ved

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$F(\\var{k^2+1})\\approx f'(\\var{k^2})(\\var{k^2+1}-\\var{k^2})+f(\\var{k^2})=\\frac{1}{2\\cdot\\var{k}}\\cdot 1+\\var{k}=\\simplify{{k+1/(2*k)}}$.

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Først, skriv inn det nærmeste tallet til $\\var{k^2+1}$ som du kan finne kvadratrota av uten kalkulator (der kvadratrota blir et heltall)

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$x_0=$[[0]]

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Finn den deriverte til $f(x)$ (Bruk sqrt(x) for å skrive $\\sqrt{x}$)

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Finn $f'(x_0)$, hvor $x_0$ er tallet du fant i a).

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Lineariseringen til $f(x)$ i punkt $x=x_0$, hvor $x_0$ er tallet du fant i a), blir

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$F(x)=f'($[[1]]$)\\cdot(x-$[[2]] $)+f($[[3]] $)\\,\\,\\,=\\,\\,\\,$[[0]]$\\cdot(x-$[[5]]$)+$[[4]]

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Finn $F(\\var{k^2+1})$. (Husk: Bruk punktum, ikke komma for å skrive desimaltall)

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Bruk kalkulator for å finne $\\sqrt{\\var{k^2+1}}$

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Sammenlikn resultatene i oppgavene e) og f)

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