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På grafen nedenfor er det gitt en funksjon $f(x)=\\simplify{{a}*x+{b}}$ som roterer en gang om $x$-aksen. Omdreiningslegemet er avgrenset av linjene $x=\\var{x1}$ og $x=\\var{x2}$.

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{geogebra_applet('https://www.geogebra.org/m/xsnnedmy',defs)}

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Volumet i opgavene a) og b) regnes ut ved bruk av formelen 

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\\[V=\\pi \\int_a^b (f(x))^2dx \\]

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Volum til kjegle i oppgavene c) og d) regnes ut ved bruk av folmelen 

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\\[V=\\dfrac{\\pi r^2 h}{3} \\]

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En av måtene å beregne volumet av dette legemet er å regne ut integralet 

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$V=\\pi\\int_{\\var{x1}}^{\\var{x2}}$[[0]]$dx$

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Volumet av legemet er lik (for å skrive inn $\\pi$ skriv pi, eller regn ut med minst tre desimaler)

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Den andre måten for å regne volumet av omdeiningslegemet er å finne differansen mellom volumet til en stor kjegle $K_1$ og volumet til en mindre, liten kjegle $K_2$.

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Finner volumet til stor kjegle $K_1$ 

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{geogebra_applet('https://www.geogebra.org/m/vyvysc6s',defs)}

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Høyden til kjegle er $h=$[[0]], radius av grunnflaten er $r=$[[1]]

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Volumet til den store kjeglen er $V_{K_1}=$[[2]]

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Finner volumet til den lille kjeglen $K_2$ 

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{geogebra_applet('https://www.geogebra.org/m/prqxcdtr',defs)}

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Høyden til kjegle er $h=$[[0]], radius av grunnflaten er $r=$[[1]]

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Volumet til den lille kjeglen er $V_{K_2}=$[[2]]

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Regn ut volumet til det opprinnelige legemet

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$V=V_{K_2}-V_{K_1}=$

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Sammenlikn resultatene fra oppgave b) og e).

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