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I denne oppgaven regner vi ut det ubestemte integralet 

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\\[ \\int (\\simplify{{b}x+{c}})\\cdot e^{x}dx\\]

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steg for steg ved bruk av delvis integrasjon. 

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Setningen som vi skal bruke sier at for funksjonene $u(x)$ og $v(x)$ som har kontinuerlige deriverte gjelder formelen

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\\[\\int u(x)\\cdot v'(x)dx=u(x)\\cdot v(x) -\\int u'(x)\\cdot v(x) dx  \\]

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Først, er funksjonene $u(x)=\\simplify{{b}x+{c}}$ og $v'(x)=e^x$

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Videre regner ut $u'(x)=\\var{b}$ og $v(x)=e^x$

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Nå bruker setningen og skriver det opprinnelige integralet som differansen og regner ut

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\\[\\int (\\simplify{{b}x+{c}})\\cdot e^{x}dx=(\\simplify{{b}x+{c}})\\cdot e^{x}-\\int \\var{b} e^x dx=(\\simplify{{b}x+{c-b}})e^x+C\\]

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Først, bestem funksjonene $u(x)=$ [[0]] og $v'(x)=$[[1]]

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Videre regn ut $u'(x)=$ [[2]] og $v(x)=$[[3]] 

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Nå bruk setningen ovenfor og skriv det opprinnelige integralet som differansen og regn ut

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$\\int (\\simplify{{b}x+{c}})\\cdot e^{x}dx=$ [[4]] $-\\int$ [[5]]$dx=$[[6]]

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