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I denne oppgaven regner vi ut det ubestemte integralet
\n\\[ \\int (\\simplify{{b}x+{c}})\\cdot e^{x}dx\\]
\nsteg for steg ved bruk av delvis integrasjon.
\nSetningen som vi skal bruke sier at for funksjonene $u(x)$ og $v(x)$ som har kontinuerlige deriverte gjelder formelen
\n\\[\\int u(x)\\cdot v'(x)dx=u(x)\\cdot v(x) -\\int u'(x)\\cdot v(x) dx \\]
", "advice": "Først, er funksjonene $u(x)=\\simplify{{b}x+{c}}$ og $v'(x)=e^x$
\nVidere regner ut $u'(x)=\\var{b}$ og $v(x)=e^x$
\nNå bruker setningen og skriver det opprinnelige integralet som differansen og regner ut
\n\\[\\int (\\simplify{{b}x+{c}})\\cdot e^{x}dx=(\\simplify{{b}x+{c}})\\cdot e^{x}-\\int \\var{b} e^x dx=(\\simplify{{b}x+{c-b}})e^x+C\\]
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\nVidere regn ut $u'(x)=$ [[2]] og $v(x)=$[[3]]
\nNå bruk setningen ovenfor og skriv det opprinnelige integralet som differansen og regn ut
\n$\\int (\\simplify{{b}x+{c}})\\cdot e^{x}dx=$ [[4]] $-\\int$ [[5]]$dx=$[[6]]
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