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Finding $x$ from a logarithmic equation of the form $\\log_x \\left(\\frac{1}{\\sqrt(a)}\\right) = \\frac{1}{2}$, for a positive integer $a$.

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Find the value of $x$:

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\\[ \\log_x \\left(\\simplify[fractionNumbers]{1/sqrt({a})}\\right) = \\frac{1}{2} \\]

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To find the value of $x$, recall that $\\log_x(a)=b$ is equivalent to $x^b=a$. 

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Therefore, \\[ \\log_x\\left(\\simplify{1/sqrt({a})}\\right) =\\frac{1}{2}\\quad \\implies \\quad x^\\frac{1}{2} = \\frac{1}{\\sqrt{\\var{a}}} \\,. \\]

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Hence, \\[ x=\\frac{1}{\\var{a}}\\,.\\]

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$x=$ [[0]] (Give your answer as a fraction where necessary.)

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