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Rewriting expressions of the form $n\\log(a)\\pm m\\log(b)$ as a single logarithm.

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Rewrite the following expression as a single logarithm:

\n

\\[\\simplify{{n1}log({a})+{n2}log({b})}.\\]

", "advice": "

{advice}

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To rewrite $\\\\simplify{{n1}log({a})+{n2}log({b})}$ as a single logarithm, we want to use the following rules:

\\n\\n

Hence,

\\n

\\\\[ \\\\begin{split} \\\\simplify{{n1}log({a})+{n2}log({b})} &\\\\,= \\\\simplify[!collectNumbers]{log({a}^{n1})+log({b}^{n2})} \\\\\\\\ &\\\\,= \\\\simplify{log({a^n1})+log({b^n2})} \\\\\\\\&\\\\,=\\\\simplify{log({sol})}. \\\\end{split} \\\\]

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To rewrite $\\\\simplify{{n1}log({a})+{n2}log({b})}$ as a single logarithm, we want to use the following rules:

\\n\\n

Hence,

\\n

\\\\[ \\\\begin{split} \\\\simplify{{n1}log({a})+{n2}log({b})} &\\\\,= \\\\simplify[!collectNumbers]{log({a}^{n1})-log({b}^{abs(n2)})} \\\\\\\\ &\\\\,=\\\\simplify{log({a^n1})-log({b^abs(n2)})} \\\\\\\\ &\\\\,=\\\\simplify[fractionNumbers]{log({sol})}. \\\\end{split} \\\\]

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