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Rewriting expressions of the form $n \\log(a)\\pm m \\log(b) \\pm p \\log(c)$ as a single logarithm.

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Rewrite the following expression as a single logarithm:

\n

\\[\\simplify{{n1}log({a})+{n2}log({b})+{n3}log({c})}.\\]

", "advice": "

{advice}

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To rewrite $\\\\simplify{{n1}log({a})+{n2}log({b})+{n3}log({c})}$ as a single logarithm, we want to use the following rules:

\\n\\n

Hence,

\\n

\\\\[ \\\\begin{split} \\\\simplify{{n1}log({a})+{n2}log({b})+{n3}log({c})} &\\\\,= \\\\simplify[!collectNumbers]{log({a}^{n1})+log({b}^{n2})+log({c}^{n3})} \\\\\\\\ &\\\\,= \\\\simplify{log({a^n1})+log({b^n2})+log({c^n3})} \\\\\\\\&\\\\,=\\\\simplify{log({sol})}. \\\\end{split} \\\\]

\"", "description": "", "templateType": "long string", "can_override": false}, "advice2": {"name": "advice2", "group": "Ungrouped variables", "definition": "\"

To rewrite $\\\\simplify{{n1}log({a})+{n2}log({b})+{n3}log({c})}$ as a single logarithm, we want to use the following rules:

\\n\\n

Hence,

\\n

\\\\[ \\\\begin{split} \\\\simplify{{n1}log({a})+{n2}log({b})+{n3}log({c})} &\\\\,= \\\\simplify[!collectNumbers]{log({a}^{n1})+log({b}^{n2})-log({c}^{abs(n3)})} \\\\\\\\ &\\\\,=\\\\simplify{log({a^n1})+log({b^n2})-log({c^abs(n3)})} \\\\\\\\ &\\\\,=\\\\simplify{log({a^n1}*{b^n2})-log({c^abs(n3)})}\\\\\\\\  &\\\\,=\\\\simplify[fractionNumbers]{log({sol})}. \\\\end{split} \\\\]

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To rewrite $\\\\simplify{{n1}log({a})+{n2}log({b})+{n3}log({c})}$ as a single logarithm, we want to use the following rules:

\\n\\n

Hence,

\\n

\\\\[ \\\\begin{split} \\\\simplify{{n1}log({a})+{n2}log({b})+{n3}log({c})} &\\\\,= \\\\simplify[!collectNumbers]{log({a}^{n1})-log({b}^{abs(n2)})+log({c}^{n3})} \\\\\\\\ &\\\\,=\\\\simplify{log({a^n1})-log({b^abs(n2)})+log({c^n3})} \\\\\\\\ &\\\\,=\\\\simplify{log({a^n1}*{c^n3})-log({b^abs(n2)})}\\\\\\\\  &\\\\,=\\\\simplify[fractionNumbers]{log({sol})}. \\\\end{split} \\\\]

\"", "description": "", "templateType": "long string", "can_override": false}, "advice4": {"name": "advice4", "group": "Ungrouped variables", "definition": "\"

To rewrite $\\\\simplify{{n1}log({a})+{n2}log({b})+{n3}log({c})}$ as a single logarithm, we want to use the following rules:

\\n\\n

Hence,

\\n

\\\\[ \\\\begin{split} \\\\simplify{{n1}log({a})+{n2}log({b})+{n3}log({c})} &\\\\,= \\\\simplify[!collectNumbers]{log({a}^{n1})-log({b}^{abs(n2)})-log({c}^{abs(n3)})} \\\\\\\\ &\\\\,=\\\\simplify{log({a^n1})-log({b^abs(n2)})-log({c^abs(n3)})} \\\\\\\\ &\\\\,=\\\\simplify{log({a^n1})-log({b^abs(n2)}*{c^abs(n3)})}\\\\\\\\  &\\\\,=\\\\simplify[fractionNumbers]{log({sol})}. \\\\end{split} \\\\]

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