// Numbas version: exam_results_page_options {"name": "Integration by parts 1 with limits", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"functions": {}, "ungrouped_variables": ["s3", "c", "b", "m", "i1", "i0"], "name": "Integration by parts 1 with limits", "tags": ["algebraic manipulation", "Calculus", "calculus", "indefinite integration", "integrals", "integration", "integration by parts", "steps", "Steps"], "advice": "

The formula for integrating by parts is

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\\[ \\int u\\frac{dv}{dx} dx = uv - \\int v \\frac{du}{dx} dx. \\]

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We choose $u = x$ and $\\displaystyle \\frac{dv}{dx} = \\simplify[std]{({b}*x+{c})^{m}}$.

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So $\\displaystyle \\frac{du}{dx}$ = $1$ and $\\displaystyle v = \\simplify[std]{(1/{(m+1)*b})*({b}*x+{c})^{m+1}}$.

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Hence,
\\[ \\begin{eqnarray*} \\displaystyle \\int^\\var{i1}_\\var{i0} \\simplify[std]{x*({b}x+{c})^{m}} dx &=& [uv]^\\var{i1}_\\var{i0} - \\int^\\var{i1}_\\var{i0} v \\frac{du}{dx} dx \\\\ &=& \\simplify[std]{[(x/{(m+1)*b})*({b}*x+{c})^{m+1}]}^\\var{i1}_\\var{i0} -\\simplify{ (1/{(m+1)*b})}*\\int^\\var{i1}_\\var{i0}(\\var{b}*x+\\var{c})^{\\var{m}+1} \\mathrm{d}x \\\\ &=& \\simplify[std]{[(x/{(m+1)*b})*({b}*x+{c})^{m+1}]}^\\var{i1}_\\var{i0} - \\simplify{(1/{(m+1)*(m+2)*b^2})*({b}*x+{c})^{m+2}}^\\var{i1}_\\var{i0} \\\\ &=&[\\simplify[std]{({b}*x+{c})^{m+1}/{(m+1)*(m+2)*b^2}*({b*(m+2)}x - ({b}x+{c}))}]^\\var{i1}_\\var{i0}\\\\ &=&[\\simplify[std]{({b}*x+{c})^{m+1}/{(m+1)*(m+2)*b^2}*({b*(m+1)}x - {c})}]^\\var{i1}_\\var{i0} \\end{eqnarray*}\\]

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The formula for integrating by parts is

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\\[ \\int u\\frac{dv}{dx} dx = uv - \\int v \\frac{du}{dx} dx. \\]

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What is the most suitable choice for $u$ and $\\frac{dv}{dx}$?

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$u=\\;$[[0]]

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$\\frac{dv}{dx}=\\;$[[1]]$+C$

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Hence find $v =\\;$[[0]] 

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and $\\frac{du}{dx} =\\;$[[1]]

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Hence $uv =\\;$[[0]]

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$\\int v\\frac{du}{dx}\\mathrm{d}x =\\;$[[1]]

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Hence $I = [uv]_\\var{i0}^\\var{i1} - \\int^\\var{i1}_\\var{i0} v\\frac{du}{dx}\\mathrm{d}x =\\;$[[1]]

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Using integration by parts, find the following indefinite integral $I=\\displaystyle \\int^\\var{i1}_\\var{i0} \\simplify[std]{x*({b}x+{c})^{m}} dx $

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You need to know that for $n \\neq -1$:

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\\[ \\int (ax+b)^n dx = \\frac{1}{a(n+1)}(ax+b)^{n+1}+C\\]

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3/08/2012:

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Added tags.

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Added description.

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Checked calculation. OK.

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Got rid of redundant instructions about inputting constant of integration.

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Got rid of instruction re not inputting decimals - no restriction needed, so no forbidden strings.

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Penalised use of steps, 1 mark. Added message to that effect.

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Improved Advice display.

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Given that $\\displaystyle \\int^i_j x({ax+b)^{m}} dx=\\frac{1}{A}(ax+b)^{m+1}g(x)+C$ for a given integer $A$ and polynomial $g(x)$, find $g(x)$.

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