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Basic potential divider questions

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Using Kirchoff's second law, determine the unknown quantities in the potential dividers below.

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a) The total e.m.f = 4 V = 3 mA$\\times$ 1 k$\\Omega$ + 3 mA $\\times$ R = total p.d. at the resistors

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3 R mA= 1 V  $\\Rightarrow$ R = $\\frac{1}{3}$ = 0.33 k $\\Omega$. 

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The p.d. across the resistor is: V = 4 - 3 mA $\\times$ 1 k$\\Omega$ = 1 V. 

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b) The combined resistance of the bulb and 2 k$\\Omega$ resistor is: $\\frac{1}{2} + \\frac{1}{2} = 1\\,\\text{k}\\Omega$. 

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The ratio of resistance across the combined resistance of the bulb and 2 k$\\Omega$ resistor to the total resistance of the circuit should be: \\[\\frac{1}{1+R} = \\frac{4}{5}\\\\4R + 4=5\\\\R=\\frac{1}{4}=0.25 \\text{k}\\Omega\\]

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What is the value of R? 

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[[0]]k$\\Omega$

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What is potential difference across R?

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[[1]] V

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What should be the value of R for the potential difference across the bulb to be 4V?

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[[0]]k$\\Omega$ 

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