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{
    "url": "https://numbas.mathcentre.ac.uk/api/questions/11733/?format=api",
    "name": "Quotient rule - differentiate exponential over exponential",
    "published": true,
    "project": "https://numbas.mathcentre.ac.uk/api/projects/601/?format=api",
    "author": {
        "url": "https://numbas.mathcentre.ac.uk/api/users/697/?format=api",
        "profile": "https://numbas.mathcentre.ac.uk/accounts/profile/697/?format=api",
        "full_name": "Newcastle University Mathematics and Statistics",
        "pk": 697,
        "avatar": {
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        }
    },
    "edit": "https://numbas.mathcentre.ac.uk/question/11733/quotient-rule-differentiate-exponential-over-exponential/?format=api",
    "preview": "https://numbas.mathcentre.ac.uk/question/11733/quotient-rule-differentiate-exponential-over-exponential/preview/?format=api",
    "download": "https://numbas.mathcentre.ac.uk/question/11733/quotient-rule-differentiate-exponential-over-exponential.zip?format=api",
    "source": "https://numbas.mathcentre.ac.uk/question/11733/quotient-rule-differentiate-exponential-over-exponential.exam?format=api",
    "metadata": {
        "notes": "\n\t\t<p><strong>1/08/2012:</strong></p>\n\t\t<p>Added tags.</p>\n\t\t<p>Added description.</p>\n\t\t<p>Checked calculation. OK.</p>\n\t\t<p>Added information about Show steps. Altered to 0 marks lost rather than 1.</p>\n\t\t<p>Changed std rule set to include !noLeadingMinus, so expressions don't change order from that intended. Got rid of a redundant ruleset.</p>\n\t\t<p>&nbsp;</p>\n\t\t",
        "licence": "Creative Commons Attribution 4.0 International",
        "description": "<p>The derivative of $\\displaystyle \\frac{a+be^{cx}}{b+ae^{cx}}$ is $\\displaystyle \\frac{pe^{cx}} {(b+ae^{cx})^2}$. Find $p$.</p>"
    },
    "status": "ok",
    "resources": []
}