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{
    "url": "https://numbas.mathcentre.ac.uk/api/questions/11749/?format=api",
    "name": "Calculate definite integral with a hyperbolic substitution",
    "published": true,
    "project": "https://numbas.mathcentre.ac.uk/api/projects/601/?format=api",
    "author": {
        "url": "https://numbas.mathcentre.ac.uk/api/users/697/?format=api",
        "profile": "https://numbas.mathcentre.ac.uk/accounts/profile/697/?format=api",
        "full_name": "Newcastle University Mathematics and Statistics",
        "pk": 697,
        "avatar": {
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    },
    "edit": "https://numbas.mathcentre.ac.uk/question/11749/calculate-definite-integral-with-a-hyperbolic-subs/?format=api",
    "preview": "https://numbas.mathcentre.ac.uk/question/11749/calculate-definite-integral-with-a-hyperbolic-subs/preview/?format=api",
    "download": "https://numbas.mathcentre.ac.uk/question/11749/calculate-definite-integral-with-a-hyperbolic-subs.zip?format=api",
    "source": "https://numbas.mathcentre.ac.uk/question/11749/calculate-definite-integral-with-a-hyperbolic-subs.exam?format=api",
    "metadata": {
        "notes": "<p><strong>30/06/2012:</strong></p>\n    <p>Added, edited tags</p>\n    <p>Slight change to prompt.</p>\n    <p>Could include standard integral in Show steps (once Show steps is available)</p>\n    <p><strong>19/07/2012:</strong></p>\n    <p>Added description.</p>\n    <p>Changed Advice on the standard integral - so that it makes sense!</p>\n    <p>Added Show steps information on the standard integral.</p>\n    <p>Checked calculation.</p>\n    <p>Set new tolerance variable tol=0 for the numeric input.</p>\n    <p><strong>23/07/2012:</strong></p>\n    <p>Added tags.</p>\n    <p>Solution always requires arccosh(x) and not arcsinh(x) or arctanh(x). Is this on purpose?</p>\n    <p>&nbsp;Question appears to be working correctly.</p>\n    <p><strong>22/12/2012:(WHF)</strong></p>\n    <p>Checked calculation, OK. Added tested1 tag.</p>\n    <p>Checked rounding, OK. Added cr1 tag.</p>\n    <p>&nbsp;</p>\n    <p><br /><br /></p>\n    <p>&nbsp;</p>",
        "licence": "Creative Commons Attribution 4.0 International",
        "description": "<p>Find (hyperbolic substitution):<br />$\\displaystyle \\int_{b}^{2b} \\left(\\frac{1}{\\sqrt{a^2x^2-b^2}}\\right)\\;dx$</p>"
    },
    "status": null,
    "resources": []
}