GET /api/questions/11923/?format=api
HTTP 200 OK
Allow: GET, HEAD, OPTIONS
Content-Type: application/json
Vary: Accept
{
"url": "https://numbas.mathcentre.ac.uk/api/questions/11923/?format=api",
"name": "Divide two numbers in $\\mathbb{Z}[\\sqrt{-2}]$",
"published": true,
"project": "https://numbas.mathcentre.ac.uk/api/projects/601/?format=api",
"author": {
"url": "https://numbas.mathcentre.ac.uk/api/users/697/?format=api",
"profile": "https://numbas.mathcentre.ac.uk/accounts/profile/697/?format=api",
"full_name": "Newcastle University Mathematics and Statistics",
"pk": 697,
"avatar": {
"20x20": "https://numbas.mathcentre.ac.uk/media/avatars/UnivNcle-shield_mKn5GZP.20x20.png",
"40x40": "https://numbas.mathcentre.ac.uk/media/avatars/UnivNcle-shield_mKn5GZP.40x40.png",
"150x150": "https://numbas.mathcentre.ac.uk/media/avatars/UnivNcle-shield_mKn5GZP.150x150.png"
}
},
"edit": "https://numbas.mathcentre.ac.uk/question/11923/divide-two-numbers-in-mathbb-z-sqrt-2/?format=api",
"preview": "https://numbas.mathcentre.ac.uk/question/11923/divide-two-numbers-in-mathbb-z-sqrt-2/preview/?format=api",
"download": "https://numbas.mathcentre.ac.uk/question/11923/divide-two-numbers-in-mathbb-z-sqrt-2.zip?format=api",
"source": "https://numbas.mathcentre.ac.uk/question/11923/divide-two-numbers-in-mathbb-z-sqrt-2.exam?format=api",
"metadata": {
"notes": "",
"licence": "Creative Commons Attribution 4.0 International",
"description": "<p>In the ring $\\mathbb{Z}[\\sqrt{-2}]$ , find the remainder $r=r_1+r_2\\sqrt{-2}$, where $a \\gt 0,\\;b \\gt 0$ , on dividing $a+b\\sqrt{-2}$ by $c+d\\sqrt{-2}$ .</p>"
},
"status": null,
"resources": []
}
