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{
    "url": "https://numbas.mathcentre.ac.uk/api/questions/199/?format=api",
    "name": "Dividing Polynomials",
    "published": true,
    "project": "https://numbas.mathcentre.ac.uk/api/projects/3/?format=api",
    "author": {
        "url": "https://numbas.mathcentre.ac.uk/api/users/6/?format=api",
        "profile": "https://numbas.mathcentre.ac.uk/accounts/profile/6/?format=api",
        "full_name": "Bill Foster",
        "pk": 6,
        "avatar": null
    },
    "edit": "https://numbas.mathcentre.ac.uk/question/199/dividing-polynomials/?format=api",
    "preview": "https://numbas.mathcentre.ac.uk/question/199/dividing-polynomials/preview/?format=api",
    "download": "https://numbas.mathcentre.ac.uk/question/199/dividing-polynomials.zip?format=api",
    "source": "https://numbas.mathcentre.ac.uk/question/199/dividing-polynomials.exam?format=api",
    "metadata": {
        "notes": "\n            \t\t            \t\t<p><strong>28/6/2012:</strong></p>\n            \t\t            \t\t    <p>Changed the divisor to $x+a$ where $a \\neq 0$, before this $a=0$ was allowed making the question easy.</p>\n            \t\t            \t\t    <p>Added decimal point . as forbidden string to stop decimal input (is this necessary?)</p>\n            \t\t            \t\t    <p>Added tags.</p>\n            \t\t            \t\t    <p>The solution is given in terms of writing the dividend polynomial as powers of the linear divisor polynomial rather than using standard polynomial long division.</p>\n            \t\t            \t\t    <p><strong>18/07/2012:</strong></p>\n            \t\t            \t\t    <p>Added description.</p>\n            \t\t            \t\t    <p><strong>23/07/2012:</strong></p>\n            \t\t            \t\t    <p>Added tags.</p>\n            \t\t            \t\t    <p>Question appears to be working correctly.</p>\n            \t\t            \t\t    <p>&nbsp;</p>\n            \t\t            \n            \t\t",
        "description": "<p>Dividing a cubic polynomial by a linear polynomial. Find quotient and remainder.</p>",
        "licence": "Creative Commons Attribution 4.0 International"
    },
    "status": null,
    "resources": []
}