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{
"url": "https://numbas.mathcentre.ac.uk/api/questions/205/?format=api",
"name": "Logarithms: Solving equations 2",
"published": true,
"project": "https://numbas.mathcentre.ac.uk/api/projects/3/?format=api",
"author": {
"url": "https://numbas.mathcentre.ac.uk/api/users/6/?format=api",
"profile": "https://numbas.mathcentre.ac.uk/accounts/profile/6/?format=api",
"full_name": "Bill Foster",
"pk": 6,
"avatar": null
},
"edit": "https://numbas.mathcentre.ac.uk/question/205/logarithms-solving-equations-2/?format=api",
"preview": "https://numbas.mathcentre.ac.uk/question/205/logarithms-solving-equations-2/preview/?format=api",
"download": "https://numbas.mathcentre.ac.uk/question/205/logarithms-solving-equations-2.zip?format=api",
"source": "https://numbas.mathcentre.ac.uk/question/205/logarithms-solving-equations-2.exam?format=api",
"metadata": {
"notes": "\n \t\t<p><strong>5/08/2012:</strong></p>\n \t\t <p>Added tags.</p>\n \t\t <p>Added description.</p>\n \t\t <p>Checked calculation.OK.</p>\n \t\t <p>Improved display in content areas.</p>\n \t\t",
"description": "\n \t\t<p>Solve for $x$: $\\displaystyle 2\\log_{a}(x+b)- \\log_{a}(x+c)=d$. </p>\n \t\t <p>Make sure that your choice is a solution by substituting back into the equation.</p>\n \t\t",
"licence": "Creative Commons Attribution 4.0 International"
},
"status": null,
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}