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{
    "url": "https://numbas.mathcentre.ac.uk/api/questions/308/?format=api",
    "name": "Logarithms: Solving equations 4",
    "published": true,
    "project": "https://numbas.mathcentre.ac.uk/api/projects/3/?format=api",
    "author": {
        "url": "https://numbas.mathcentre.ac.uk/api/users/6/?format=api",
        "profile": "https://numbas.mathcentre.ac.uk/accounts/profile/6/?format=api",
        "full_name": "Bill Foster",
        "pk": 6,
        "avatar": null
    },
    "edit": "https://numbas.mathcentre.ac.uk/question/308/logarithms-solving-equations-4/?format=api",
    "preview": "https://numbas.mathcentre.ac.uk/question/308/logarithms-solving-equations-4/preview/?format=api",
    "download": "https://numbas.mathcentre.ac.uk/question/308/logarithms-solving-equations-4.zip?format=api",
    "source": "https://numbas.mathcentre.ac.uk/question/308/logarithms-solving-equations-4.exam?format=api",
    "metadata": {
        "notes": "\n                        \t\t<p><strong>2/06/2012:</strong></p>\n                        \t\t<p>Added tags.</p>\n                        \t\t<p>Improved display.</p>\n                        \t\t<p>Forced solution in second part to be accurate to 3 decimal places with no tolerance.</p>\n                        \t\t<p>&nbsp;<strong>19/07/2012:</strong></p>\n                        \t\t<p>Added description.</p>\n                        \t\t<p>Checked calculation.</p>\n                        \t\t<p><strong>25/07/2012:</strong></p>\n                        \t\t<p>Added tags.</p>\n                        \t\t<p>Corrected a typo.</p>\n                        \t\t<p>In the Advice section moved \\Rightarrow so that it is at the beginning of the line instead of the end of the previous line.</p>\n                        \t\t<p>Question appears to be working correctly.</p>\n                        \t\t<p>&nbsp;</p>\n                        \t\t<p>&nbsp;</p>\n                        \t\t",
        "description": "<p>Solve for $x$ each of the following equations:&nbsp;$n^{ax+b}=m^{cx}$ and $p^{rx^2}=q^{sx}$.</p>",
        "licence": "Creative Commons Attribution 4.0 International"
    },
    "status": null,
    "resources": []
}