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{
    "url": "https://numbas.mathcentre.ac.uk/api/questions/7129/?format=api",
    "name": "Inverse Matrix",
    "published": true,
    "project": "https://numbas.mathcentre.ac.uk/api/projects/4/?format=api",
    "author": {
        "url": "https://numbas.mathcentre.ac.uk/api/users/7/?format=api",
        "profile": "https://numbas.mathcentre.ac.uk/accounts/profile/7/?format=api",
        "full_name": "Christian Lawson-Perfect",
        "pk": 7,
        "avatar": {
            "20x20": "https://numbas.mathcentre.ac.uk/media/avatars/clp-2023_OVPD4En.20x20.jpg",
            "40x40": "https://numbas.mathcentre.ac.uk/media/avatars/clp-2023_OVPD4En.40x40.jpg",
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        }
    },
    "edit": "https://numbas.mathcentre.ac.uk/question/7129/inverse-matrix/?format=api",
    "preview": "https://numbas.mathcentre.ac.uk/question/7129/inverse-matrix/preview/?format=api",
    "download": "https://numbas.mathcentre.ac.uk/question/7129/inverse-matrix.zip?format=api",
    "source": "https://numbas.mathcentre.ac.uk/question/7129/inverse-matrix.exam?format=api",
    "metadata": {
        "notes": "<h4><strong><br /></strong>January 2015</h4>\n<p>Rewritten by CP to use the matrix entry part type.</p>\n<p>Why do we zero the second column in two different stages? The algorithm is clearer to me if it goes:</p>\n<ul>\n<li>zero rows 2 and 3 column 1 using row 1</li>\n<li>make sure there's a 1 in the second column of row 2</li>\n<li>zero rows 1 and 3 column 2 using row 2</li>\n<li>make sure there's a 1 in the third column of row 3</li>\n<li>zero rows 1 and 2 column 3 using row 3</li>\n</ul>\n<p><strong>&nbsp;</strong></p>\n<p><strong>5/07/2012:</strong></p>\n<p>Added tags.</p>\n<p>Changed grammar in the question.</p>\n<p>Question appears to be working correctly.</p>\n<p><strong>14/07/2012:</strong></p>\n<p>Need to align columns where input takes place through the stages.</p>",
        "description": "<p>$A$ a $3 \\times 3$ matrix. Using row operations on the augmented matrix $\\left(A | I_3\\right)$ reduce to $\\left(I_3 | A^{-1}\\right)$.</p>",
        "licence": "Creative Commons Attribution 4.0 International"
    },
    "status": "ok",
    "resources": []
}