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"url": "https://numbas.mathcentre.ac.uk/api/questions/86/?format=api",
"name": "Quotient rule",
"published": true,
"project": "https://numbas.mathcentre.ac.uk/api/projects/3/?format=api",
"author": {
"url": "https://numbas.mathcentre.ac.uk/api/users/6/?format=api",
"profile": "https://numbas.mathcentre.ac.uk/accounts/profile/6/?format=api",
"full_name": "Bill Foster",
"pk": 6,
"avatar": null
},
"edit": "https://numbas.mathcentre.ac.uk/question/86/quotient-rule/?format=api",
"preview": "https://numbas.mathcentre.ac.uk/question/86/quotient-rule/preview/?format=api",
"download": "https://numbas.mathcentre.ac.uk/question/86/quotient-rule.zip?format=api",
"source": "https://numbas.mathcentre.ac.uk/question/86/quotient-rule.exam?format=api",
"metadata": {
"notes": "\n \t\t<p><strong>1/08/2012:</strong></p>\n \t\t<p>Added tags.</p>\n \t\t<p>Checked calculation. OK.</p>\n \t\t<p>Added description.</p>\n \t\t<p>All round improvement in display.</p>\n \t\t<p>Added forbidden instructions on using decimals.</p>\n \t\t<p>Added information on losing 1 mark if use Show steps in part a).</p>\n \t\t",
"description": "<p>Other method. Find $p,\\;q$ such that $\\displaystyle \\frac{ax+b}{cx+d}= p+ \\frac{q}{cx+d}$. Find the derivative of $\\displaystyle \\frac{ax+b}{cx+d}$.</p>",
"licence": "Creative Commons Attribution 4.0 International"
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}