Q5 Oil tanks problems

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TEAME CIT

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TEAME CIT 8 years, 9 months ago

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TEAME CIT 9 years, 3 months ago

Created this.

Name	Status	Author	Last Modified
Q5 Oil tanks problems	draft	TEAME CIT	07/10/2016 10:16
Simon's copy of Q5 Oil tanks problems	draft	Simon Thomas	21/02/2019 11:05

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Question statement

Solve the following oil tank questions to the nearest euro.

Give any introductory information the student needs.

			Name	Type	Generated Value

size	list	[ 3.5, 3.09, 2.99, 3.06 ]
dia	list	[ 1.24, 1.57 ]
per	list	[ 90, 70 ]
price	list	[ 87.5, 78.8, 79.8 ]
vol1	number	1.9860756057
dia1	integer	850
ans1	number	1564.0345394819
vol2	number	3.7315711876
ans2	number	2940.4780957999
vol3	number	14.364558
ans3	number	11462.917284

Automatically regenerate variables?

Name

Data type

Value

xxxxxxxxxx
 
shuffle(2.6..3.75#0.01)[0..4]

JME function reference

Description

Describe what this variable represents, and list any assumptions made about its value.

Can an exam override the value of this variable?

Generated value: `list`

[ 3.5, 3.09, 2.99, 3.06 ]

→ Used by:

vol1
vol2
vol3

Advice
"Part a)" - prompt
"Part b)" - prompt
"Part c)" - prompt

Parts

Part a) Gap-fill
1. Gap Number entry
  Add
1. Step Information only
Part b) Gap-fill
1. Gap Number entry
  Add
1. Step Information only
Part c) Gap-fill
1. Gap Number entry
  Add

Gap-fill

Ask the student a question, and give any hints about how they should answer this part.

A rectangular oil tank has dimensions $\var{size[2]}m$ by $\var{size[3]}m$ by $\var{dia[1]}m$ . Find the cost to fill this tank if the fuel is priced at $\var{price[2]}$ cent per litre.

€Unnamed gap

Advice

N.B

$1m = 1000mm$

$1m^3 = 1000$ litres

Part 1

Volume of cylindrical oil tank

V = $\pi r^2h$

V = $\pi \times(\frac{\var{dia1}}{2\times1000})^2 \times \var{size[0]} = \var{vol1}$

Ans = $\var{vol1} \times 1000 \times (\frac{\var{price[0]}}{100}) \times (\frac{\var{per[0]}}{100}) = \var{ans1}$

Part 2

Volume of cylindrical oil tank

V = $\pi r^2h$

V = $\pi \times(\frac{\var{dia[0]}}{2})^2 \times \var{size[1]} = \var{vol2}$

Ans = $\var{vol2} \times 1000 \times (\frac{\var{price[1]}}{100}) = \var{ans2}$

Part 3

V = length $\times$ breadth $\times$ height

V = $\var{size[2]} \times \var{size[3]} \times \var{dia[1]} = \var{vol3}$

Ans = $\var{vol3} \times 1000 \times (\frac{\var{price[2]}}{100}) = \var{ans3}$

Give a worked solution to the whole question.

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Metadata

Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

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Checkpoint description

TEAME CIT 8 years, 9 months ago

TEAME CIT 9 years, 3 months ago

Error in variable testing condition

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Generated value: `list`

Parts

Gap-fill

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Q5 Oil tanks problems

Metadata

Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

Contributors

History

Comment

Checkpoint description

TEAME CIT 8 years, 9 months ago

TEAME CIT 9 years, 3 months ago

Error in variable testing condition

Error

Warning

Generated value: list

Parts

Gap-fill

Generated value: `list`