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Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
Contributors
History
Name | Status | Author | Last Modified | |
---|---|---|---|---|
Q2 Indices in their simplest form 2 | draft | TEAME CIT | 08/10/2016 22:21 | |
Julie's copy of Q2 Indices in their simplest form 2 | draft | Julie Crowley | 15/11/2016 15:00 |
Name | Type | Generated Value |
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num11 | list |
[ 5, 2, 4, 3 ]
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num111 | integer |
3
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ans11 | number |
12
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num12 | list |
[ 2, 5, 3, 4 ]
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num121 | integer |
3
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ans12a | number |
3
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ans12b | number |
-3
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num131 | integer |
2
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num132 | integer |
4
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ans13a | integer |
2
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num13 | list |
[ 9, 4, 5, 6, 3, 2 ]
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ans13b | number |
3
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ans13c | number |
-7
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ans13d | number |
7
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num141 | integer |
4
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num142 | integer |
8
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ans14a1 | integer |
4
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ans14b | number |
6
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num143 | integer |
3
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num14 | list |
[ 4, 3, 5, 2, 8 ]
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ans14c | number |
-12
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ans14d | number |
-39
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ans14aT | number |
64
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num21 | list |
List of 10 items
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num211 | list |
[ 5, 7, 3 ]
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ans21a | integer |
15
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ans21b | integer |
7
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ans21c | number |
10
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ans21d | number |
-1
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ans21e | number |
-18
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num22 | list |
List of 10 items
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num221 | list |
[ 3, 7, 5 ]
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ans22a | integer |
15
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ans22b | integer |
7
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ans22c | number |
16
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ans22d | number |
-5
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ans22e | number |
12
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num31 | list |
[ 3, 2, 6 ]
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ans31 | number |
-1
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num32 | list |
[ 8, 7, 3 ]
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ans32 | number |
4
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num321 | list |
[ 25, 49 ]
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num33 | list |
[ 6, 8, 2, 4, 7 ]
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ans33a | number |
5
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ans33b | number |
7
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ans33c | number |
4
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ans33d | number |
-6
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ans33e | number |
-3
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ans14a | rational |
8
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ans |
Definition of variable
ans is empty. |
|||||
power |
Definition of variable
power is empty. |
Generated value: list
- ans11
- "Part a)" - prompt
Parts
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Part a)
Gap-fill
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Part b)
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Number entry
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Gap 0.
Number entry
Gap-fill
Ask the student a question, and give any hints about how they should answer this part.
Simplify each of the following, without using a calculator:
i) [3{num11[0]}.9{num11[1]}3−{num11[2]}.27{num11[3]}]{num111}
anspower= {
ii) [5{num12[0]}.7{num12[1]}5{num12[2]}.7{num12[3]}]−{num121}
anspower= {
iii) {num132}x{num13[0]}.y−{num13[1]}.z{num13[2]}{num131}x{num13[3]}.y{num13[4]}.z−{num13[5]}
anspower= {
iv) ({num142}a{num14[0]}.b−{num14[1]}.c−{num14[2]}{num141}a{num14[3]}.b.c{num14[4]}){num143}
anspower= {
Use this tab to check that this question works as expected.
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Information only |
This question is used in the following exams: