Solving equations

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Bill Foster

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Ready to use

6 years, 6 months ago

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Bill Foster 6 years, 6 months ago

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Newcastle University Mathematics and Statistics 9 years, 3 months ago

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Name	Status	Author	Last Modified
Solving equations	Ready to use	Newcastle University Mathematics and Statistics	20/11/2019 14:50
Luis's copy of Solving equations	draft	Luis Hernandez	30/11/2018 00:49
Maria's copy of Solving equations	draft	Maria Aneiros	29/05/2019 05:08

There are 5 other versions that do you not have access to.

Question statement

Solve the following simultaneous equations for $x$ and $y$ . Input your answers as fractions or integers, not as decimals.

Give any introductory information the student needs.

			Name	Type	Generated Value

a	integer	7
c	integer	4
b	integer	7
that	number	7
this	number	4
sc1	integer	-1
s1	integer	1
s6	integer	-1
a1	integer	3
aort	string	take away the equation
a2	number	7
b1	integer	4
b2	integer	3
sc	integer	1
sb	integer	1
sa	integer	1
fromorto	string	from
c1	integer	-9

Automatically regenerate variables?

Name

Data type

Value

xxxxxxxxxx
 
sa*random(2..9)

JME function reference

Description

Describe what this variable represents, and list any assumptions made about its value.

Can an exam override the value of this variable?

Generated value: `integer`

← Depends on:

This variable doesn't seem to be used anywhere.

Parts

Gap-fill
1. Gap Gap 0. Mathematical expression
  Add
2. Gap Gap 1. Mathematical expression
  Add

Gap-fill

Ask the student a question, and give any hints about how they should answer this part.

$\begin{eqnarray} \simplify[std]{{a}x+{b}y}&=&\var{c}\\ \simplify[std]{{a1}x+{b1}y}&=&\var{c1} \end{eqnarray}$

$x=\phantom{{}}$ Gap 0., $y=\phantom{{}}$ Gap 1.

Input your answers as fractions or integers, not as decimals.

Advice

$\begin{eqnarray} \simplify[std]{{a}x+{b}y}&=&\var{c}&\mbox{ ........(1)}\\ \simplify[std]{{a1}x+{b1}y}&=&\var{c1}&\mbox{ ........(2)} \end{eqnarray}$
To get a solution for

$x$ multiply equation (1) by {this} and equation (2) by {that}

This gives:

$\begin{eqnarray} \simplify[std]{{a*this}x+{b*this}y}&=&\var{this*c}&\mbox{ ........(3)}\\ \simplify[std]{{a1*that}x+{b1*that}y}&=&\var{that*c1}&\mbox{ ........(4)} \end{eqnarray}$
Now {aort} (4) {fromorto} equation (3) to get

$\simplify[std]{({a*this}+{s6*a1*that})x={this*c}+{s6*that*c1}}$
And so we get the solution for

$x$ :

$x = \simplify{{c*b1-b*c1}/{b1*a-a1*b}}$
Substituting this value into any of the equations (1) and (2) gives:

$y = \simplify{{c*a1-a*c1}/{b*a1-a*b1}}$
You can check that these solutions are correct by seeing if they satisfy both equations (1) and (2) by substituting these values into the equations.

Give a worked solution to the whole question.

Use this tab to check that this question works as expected.

There was an error which means the tests can't run:

Part	Test	Passed?
Gap-fill
Gap-fill		Hasn't run yet
Mathematical expression
Mathematical expression		Hasn't run yet
Mathematical expression
Mathematical expression		Hasn't run yet

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Taxonomy: mathcentre

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Bill Foster 6 years, 6 months ago

Newcastle University Mathematics and Statistics 9 years, 3 months ago

Error in variable testing condition

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Generated value: `integer`

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Gap-fill

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Solving equations

Metadata

Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

Contributors

Feedback

History

Comment

Checkpoint description

Bill Foster 6 years, 6 months ago

Newcastle University Mathematics and Statistics 9 years, 3 months ago

Error in variable testing condition

Error

Warning

Generated value: integer

Parts

Gap-fill

Generated value: `integer`