20122013 CBA0_4

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Bill Foster

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Has some problems

6 years, 3 months ago

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Bill Foster commented 6 years, 3 months ago

Calculations are correct.

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Bill Foster commented 6 years, 3 months ago

Should say in part b) input to 4 decimal places.

Display of table in statement could be tidied up.

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Bill Foster 6 years, 3 months ago

Gave some feedback: Has some problems

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Newcastle University Mathematics and Statistics 9 years, 2 months ago

Created this.

Name	Status	Author	Last Modified
20122013 CBA0_4	Has some problems	Newcastle University Mathematics and Statistics	20/11/2019 14:51
Alex's copy of 20122013 CBA0_4	draft	Alex Van den Hof	31/03/2017 11:40

There is one other version that you do not have access to.

Question statement

Suppose that the discrete random variable $X$ has the probability function:

$x$	$\var{v[0][0]}$		$\var{v[1][0]}$		$\var{v[2][0]}$
$P(X=x)$	$\var{p0}$		$\var{p1}$		$\var{p2}$

Answer the following questions:

Give any introductory information the student needs.

			Name	Type	Generated Value

p2	number	0.50
p0	number	0.1
p1	number	0.4
ex1	number	0.1481
tex1	number	0.1480555556
tex2	number	4409.0030261329
ex2	number	4409.0030
tol	number	0.0001
v	list	Nested 3×2 list

Automatically regenerate variables?

Name

Data type

Value

xxxxxxxxxx
 
precround(1-p0-p1,2)

JME function reference

Description

Describe what this variable represents, and list any assumptions made about its value.

Can an exam override the value of this variable?

Generated value: `number`

0.50

← Depends on:

→ Used by:

tex1
tex2
v

Parts

Part a) Gap-fill
1. Gap Number entry
  Add
Part b) Gap-fill
1. Gap Number entry
  Add

Gap-fill

Ask the student a question, and give any hints about how they should answer this part.

Find

$\displaystyle \operatorname{E}\left[\frac{1}{X}\right]=\;$ ?Unnamed gap (Input to 4 decimal places).

Advice

If $Y$ is a discrete random variable which can take values $v_1,\;v_2,\ldots,v_n$ with corresponding probabilities $p_1,\;p_2,\ldots,p_n$ then the expected value is given by:

$\operatorname{E}[Y]=\sum_{i=1}^n p_iv_i$

a) $\displaystyle Y=\frac{1}{X} \Rightarrow \operatorname{E}[Y]=\simplify[basic]{{p0}*(1/{v[0][0]})+{p1}*(1/{v[1][0]})+{p2}*(1/{v[2][0]})}=\var{ex1}$ to 4 decimal places.

b) $\displaystyle Y=e^X \Rightarrow \operatorname{E}[Y]=\simplify[basic]{{p0}*e^{v[0][0]}+{p1}*e^{v[1][0]}+{p2}*e^{v[2][0]}}=\var{ex2}$ to 4 decimal places.

Give a worked solution to the whole question.

Use this tab to check that this question works as expected.

There was an error which means the tests can't run:

Part	Test	Passed?
Gap-fill
Gap-fill		Hasn't run yet
Number entry
Number entry		Hasn't run yet
Gap-fill
Gap-fill		Hasn't run yet
Number entry
Number entry		Hasn't run yet

This question is used in the following exams:

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Metadata

Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

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Checkpoint description

Bill Foster commented 6 years, 3 months ago

Bill Foster commented 6 years, 3 months ago

Bill Foster 6 years, 3 months ago

Newcastle University Mathematics and Statistics 9 years, 2 months ago

Error in variable testing condition

Error

Warning

Generated value: `number`

Parts

Gap-fill

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Error

20122013 CBA0_4

Metadata

Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

Contributors

Feedback

History

Comment

Checkpoint description

Bill Foster commented 6 years, 3 months ago

Bill Foster commented 6 years, 3 months ago

Bill Foster 6 years, 3 months ago

Newcastle University Mathematics and Statistics 9 years, 2 months ago

Error in variable testing condition

Error

Warning

Generated value: number

Parts

Gap-fill

Generated value: `number`