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Perform a t-test to decide if two sample means differ, ,
Given two sets of data, sample mean and sample standard deviation, on performance on the same task, make a decision as to whether or not the mean times differ. Population variance not given, so the t test has to be used in conjunction with the pooled sample standard deviation.
Link to use of t tables and p-values in Show steps.
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
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History
Newcastle University Mathematics and Statistics 9 years, 1 month ago
Created this.Name | Status | Author | Last Modified | |
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Perform a t-test to decide if two sample means differ, , | draft | Newcastle University Mathematics and Statistics | 20/11/2019 14:50 | |
Simon's copy of Perform a t-test to decide if two sample means differ, , | draft | Simon Thomas | 05/06/2019 15:28 |
There are 6 other versions that do you not have access to.
Name | Type | Generated Value |
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sd1 | integer |
70
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||||
pval | integer |
0
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||||
evi1 | list |
List of 4 items
|
||||
crit | list |
[ 1.701, 2.048, 2.763 ]
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||||
correctc | string |
There is insufficent evidence
|
||||
tval1 | number |
0.7496720902
|
||||
things | string |
male employees
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||||
m1 | integer |
330
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||||
tol | number |
0.001
|
||||
units | string |
seconds
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||||
pm | list |
List of 4 items
|
||||
tpsd | number |
73.0616178304
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||||
that | string |
the average time spent on the
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psd | number |
73.062
|
||||
fac | string |
There is evidence to suggest t
|
||||
confl | list |
[ 90, 95, 99 ]
|
||||
evi | list |
List of 4 items
|
||||
mm | list |
[ 1, 0, 0, 0 ]
|
||||
dothis | string |
retain
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||||
m | integer |
310
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||||
dmm | list |
[ 1, 0 ]
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||||
n | integer |
29
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||||
this | string |
A call centre company wants to
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||||
tval | number |
0.750
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||||
n1 | integer |
15
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||||
n2 | integer |
15
|
||||
things1 | string |
female employees
|
||||
sd | integer |
76
|
Generated value: integer
This variable doesn't seem to be used anywhere.
Parts
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Step 1: Null hypothesis
If $\mu_M$ is the mean for time spent by {things} and $\mu_F$ is the mean for time spent by {things1} then you are given that:
$\operatorname{H}_0\;:\;\mu_M=\mu_F$.
Step 2: Alternative Hypothesis
$\operatorname{H}_1\;:\;\mu_M \neq \mu_F$.
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