Distributive law: expanding one set of brackets

Error

There was an error loading the page.

Contributors

Nasir Firoz Khan

History

○

Nasir Firoz Khan 8 years, 8 months ago

Created this as a copy of Distributive law: expanding one set of brackets.

Name	Status	Author	Last Modified
Distributive law: expanding one set of brackets	Ready to use	Ben Brawn	13/02/2025 22:47
Factorising: Common factor	Ready to use	Ben Brawn	25/03/2025 23:43
Distributive law: expanding one set of brackets	draft	steve kilgallon	23/08/2017 11:12
Expanding one set of brackets	Needs to be tested	Nasir Firoz Khan	05/08/2016 16:23
Distributive law: expanding one set of brackets	draft	Nasir Firoz Khan	29/07/2016 12:57
Algebra II:Expanding one set of brackets	Ready to use	Nasir Firoz Khan	12/08/2016 15:30
Algebra II:Expanding one set of brackets	Ready to use	Nasir Firoz Khan	12/08/2016 16:16
Rachel's copy of Distributive law: expanding one set of brackets	draft	Rachel Staddon	20/04/2017 14:50
Distributive law: expanding one set of brackets	draft	Owen Jepps	11/01/2018 06:07
Marlon's copy of Factorising: Common factor	draft	Marlon Arcila	03/02/2018 16:30
Algebra II:Expanding one set of brackets	draft	heike hoffmann	14/11/2018 21:00
Factorising: Common factor	Ready to use	heike hoffmann	14/11/2018 21:07
Gemeenschappelijke factor afzonderen	draft	Johan Maertens	20/08/2019 15:38
Joshua's copy of Distributive law: expanding one set of brackets	draft	Joshua Calcutt	06/08/2019 05:55
Distributive law: expanding brackets general	Ready to use	Don Shearman	02/02/2023 23:55
Distributive law: expanding one set of brackets: student types entire answer	Ready to use	Ben Brawn	13/02/2025 22:44
Distributive law: negative sign outside of brackets	Ready to use	Ben Brawn	13/02/2025 21:42

There are 42 other versions that do you not have access to.

Question statement

In the following questions, expand the bracket and express in linear variables.

For more information, please check this video- https://www.youtube.com/watch?v=9r6_wDpxKjQ

Give any introductory information the student needs.

			Name	Type	Generated Value

pmult	integer	11
pxcoeff	integer	2
pconstant	integer	5
primes	list	[ 11, 2, 5 ]

			Name	Type	Generated Value

nmult	integer	-8
nxcoeff	integer	4
nconstant	integer	-4

			Name	Type	Generated Value

cx	integer	6
cy	integer	-9
cc	integer	8

			Name	Type	Generated Value

Automatically regenerate variables?

Name

Data type

Value

xxxxxxxxxx
 
primes[0]

JME function reference

Description

Describe what this variable represents, and list any assumptions made about its value.

Can an exam override the value of this variable?

Generated value: `integer`

← Depends on:

primes

→ Used by:

"Part a)" - prompt
"Part a)" → "Gap 0." - Minimum accepted value
"Part a)" → "Gap 0." - Maximum accepted value
"Part a)" → "Gap 1." - Minimum accepted value
"Part a)" → "Gap 1." - Maximum accepted value

Parts

Part a) Gap-fill
1. Gap Gap 0. Number entry
  Add
2. Gap Gap 1. Number entry
  Add
1. Step Information only
Part b) Gap-fill
1. Gap Gap 0. Number entry
  Add
2. Gap Gap 1. Number entry
  Add
1. Step Information only
Part c) Gap-fill
1. Gap Gap 0. Number entry
  Add
2. Gap Gap 1. Number entry
  Add
3. Gap Gap 2. Number entry
  Add
1. Step Information only

Gap-fill

Ask the student a question, and give any hints about how they should answer this part.

The expression $\var{pmult}(\var{pxcoeff}x+\var{pconstant})$ is factorised (written as a product), we can expand the expression (so it is written as a sum) to get

Gap 0. $x$ + Gap 1.

Advice

Expanding brackets involves removing the brackets from an expression by multiplying out the brackets. This is achieved by multiplying every term inside the bracket by the term outside the bracket.

Example 1- Expand: $3 (x + 6)$

a) Remember to multiply every term inside the brackets by the term outside:

$3 (x + 6) = 3 \times x + 3 \times 6 = 3 x + 18$ .

When multiplying out double brackets, every term in the first pair of brackets must be multiplied by each term in the second. When expanding brackets, be very careful when dealing with negative numbers. Multiplying negatives has special rules: a negative times a positive gives a negative, but multiplying two negatives gives a positive:

$6 (4 a - 10) = 24 a - 60$

Give a worked solution to the whole question.

Use this tab to check that this question works as expected.

There was an error which means the tests can't run:

Part	Test	Passed?
Gap-fill
Gap-fill		Hasn't run yet
Number entry
Number entry		Hasn't run yet
Number entry
Number entry		Hasn't run yet
Information only
Gap-fill
Gap-fill		Hasn't run yet
Number entry
Number entry		Hasn't run yet
Number entry
Number entry		Hasn't run yet
Information only
Gap-fill
Gap-fill		Hasn't run yet
Number entry
Number entry		Hasn't run yet
Number entry
Number entry		Hasn't run yet
Number entry
Number entry		Hasn't run yet
Information only

This question is not used in any exams.

Loading...

Error

Distributive law: expanding one set of brackets

Metadata

Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

Contributors

History

Comment

Checkpoint description

Nasir Firoz Khan 8 years, 8 months ago

Error in variable testing condition

Error

Warning

Generated value: `integer`

Parts

Gap-fill

Loading...

Error

Distributive law: expanding one set of brackets

Metadata

Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

Contributors

History

Comment

Checkpoint description

Nasir Firoz Khan 8 years, 8 months ago

Error in variable testing condition

Error

Warning

Generated value: integer

Parts

Gap-fill

Generated value: `integer`