Q1 Constant Acceleration

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Stephen Bowlzer

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Stephen Bowlzer 8 years, 7 months ago

Created this as a copy of Resolve forces on particle in equilibrium.

Name	Status	Author	Last Modified
Resolve forces on particle in equilibrium	Ready to use	Amy Chadwick	04/08/2016 11:56
Q1 Constant Acceleration	draft	Stephen Bowlzer	09/08/2016 13:08
Q2 Constant Acceleration	draft	Stephen Bowlzer	09/08/2016 14:57
John's copy of Resolve forces on particle in equilibrium	draft	John Bridges	19/09/2016 00:00
Simon's copy of Resolve forces on particle in equilibrium	draft	Simon Thomas	04/04/2019 15:26

Question statement

A car is moving along a straight road with uniform acceleration

The car passes a point A with a speed of $\var{u}\,ms^{-1}$ and another point B with a speed of $\var{v}\,ms^{-1}$

The distance from A to B is $\var{s}\,m$

(a) Find the time taken by the car to move from A to B

M is the mid-point of AB

(b) Find the speed with which the car passes M

Give any introductory information the student needs.

			Name	Type	Generated Value

s	integer	600
u	integer	10
v	integer	38
a	rational	28/25
t	rational	25
v1	decimal	dec("2.778488797889960901686509408205710885863e+1")
s1	rational	300

Automatically regenerate variables?

Name

Data type

Value

A random number between and (inclusive) with step size

Description

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Generated value: `integer`

600

This variable doesn't seem to be used anywhere.

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Part b) Gap-fill
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The time taken by the car to move from A to B = Unnamed gap seconds

Advice

(a)	$u = \var{u}; v = \var{v}; s = \var{s}; t = \,?$

	Using $s = \frac{1}{2}(u+v)t\,\,$ and rearranging for $t$ gives

	$t = \frac{2 \times s}{u+v} = \frac{2 \times \var{s}}{\var{u}+\var{v}} = \var{precround(t,3)}\,$ seconds

(b)	Find the acceleration of the car using $v = u + at$

	$a = \frac{v-u}{t} = \frac{\var{v}-\var{u}}{\var{precround(t,3)}} = \var{precround(a,3)}\,ms^{-2}$



	Then for the car travelling from A to M, we have
	$u = \var{u}; v = \,?; a = \var{precround(a,3)}; s = \var{precround(s1,2)}$

	Using $v^{2} = u^{2}+2as$ gives

	$v^{2} = (\var{u})^{2}+(2 \times \var{precround(a,3)} \times \var{s})$

	$v = \var{precround(v1,3)}\,ms^{-1}$

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This question is used in the following exam:

H1 Constant Acceleration by Stephen Bowlzer in Stephen's workspace.

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Stephen Bowlzer 8 years, 7 months ago

Error in variable testing condition

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Generated value: `integer`

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Q1 Constant Acceleration

Metadata

Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

Contributors

History

Comment

Checkpoint description

Stephen Bowlzer 8 years, 7 months ago

Error in variable testing condition

Error

Warning

Generated value: integer

Parts

Gap-fill

Generated value: `integer`