Q2 Constant Acceleration

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Stephen Bowlzer

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Stephen Bowlzer 8 years, 7 months ago

Created this as a copy of Q1 Constant Acceleration.

Name	Status	Author	Last Modified
Resolve forces on particle in equilibrium	Ready to use	Amy Chadwick	04/08/2016 11:56
Q1 Constant Acceleration	draft	Stephen Bowlzer	09/08/2016 13:08
Q2 Constant Acceleration	draft	Stephen Bowlzer	09/08/2016 14:57
John's copy of Resolve forces on particle in equilibrium	draft	John Bridges	19/09/2016 00:00
Simon's copy of Resolve forces on particle in equilibrium	draft	Simon Thomas	04/04/2019 15:26

Question statement

A sprinter emerges from the blocks with an initial speed of $\var{u}\,ms^{-1}$ and accelerates uniformly at $\var{a}\,ms^{-2}$ for the first $\var{t}\,$ seconds of a $\var{s}\,$ metre race

The sprinter then maintains a constant speed to the end of the race

Assuming the sprinter moves in a straight line

(a) Find the distance travelled by the sprinter in the first $\var{t}\,$ seconds

(b) Find the speed of the sprinter at the end of the first $\var{t}\,$ seconds

Give any introductory information the student needs.

			Name	Type	Generated Value

s	integer	400
u	number	4
a	number	1.75
t	integer	4
s1	number	30
v1	number	11
t1	number	37.6363636364
s2	number	370
t2	number	33.6363636364

Automatically regenerate variables?

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Data type

Value

A random number between and (inclusive) with step size

Description

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Generated value: `integer`

400

This variable doesn't seem to be used anywhere.

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Part b) Gap-fill
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The distance travelled by the sprinter in the first $\var{t}\,$ seconds = Unnamed gap metres

Advice

(a)	$u = \var{u}; a = \var{a}; t = \var{t}; s = \,?$

	Using $s = ut+\frac{1}{2}at^{2}$ gives

	$s = (\var{u} \times \var{t})+(\frac{1}{2}\times\var{a}\times(\var{t})^{2}) = \var{precround(s1,3)}\,$ metres

(b)	Find the speed of the sprinter after $\var{t}$ seconds using $v = u + at$

	$v = \var{u}+(\var{a}\times\var{t}) = \var{precround(v1,3)}\,ms^{-1}$

(c)	After the first $\var{t}$ seconds, the sprinter runs the remainder of the race $(\var{s}-\var{precround(s1,3)})\,$ metres at a constant speed of $\var{precround(v1,3)}\,ms^{-1}$

	So the time to run the remainder of the race is $\frac{\var{s}-\var{precround(s1,3)}}{\var{precround(v1,3)}} = \var{precround(t2,3)}\,$ seconds

	Total time for the $\var{s}\,$ metre race is then $\var{precround(t2,3)}+\var{t} = \var{precround(t1,3)}\,$ seconds

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This question is used in the following exam:

H1 Constant Acceleration by Stephen Bowlzer in Stephen's workspace.

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Taxonomy: mathcentre

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Stephen Bowlzer 8 years, 7 months ago

Error in variable testing condition

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Generated value: `integer`

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Q2 Constant Acceleration

Metadata

Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

Contributors

History

Comment

Checkpoint description

Stephen Bowlzer 8 years, 7 months ago

Error in variable testing condition

Error

Warning

Generated value: integer

Parts

Gap-fill

Generated value: `integer`