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Rearrange a homogeneous circle equation into the form (x-xc)^2+(y-yc)^2=r^2 to find the centre and radius.
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Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
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Merryn Horrocks | said | Ready to use | 11 months, 1 week ago |
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Merryn Horrocks 11 months, 1 week ago
Published this.Merryn Horrocks 11 months, 1 week ago
Gave some feedback: Ready to use
Merryn Horrocks 11 months, 1 week ago
Created this.There is only one version of this question that you have access to.
Name | Type | Generated Value |
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Cx | integer |
1
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Cy | integer |
-5
|
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R2 | integer |
1
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R | expression |
1
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||||
const | integer |
25
|
||||
eqn | expression |
x^2 + y^2 - 2x + 10y + 25=0
|
Name | Type | Generated Value |
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graph | jsxgraphboard |
HTML node
|
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xmin | integer |
-1
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ymin | integer |
-7
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xmaxtemp | integer |
3
|
||||
ymaxtemp | integer |
1
|
||||
xmax | integer |
7
|
||||
ymax | integer |
1
|
Name | Type | Generated Value |
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Generated value: integer
This variable doesn't seem to be used anywhere.
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Begin by completing the square separately on the $x-$terms and the $y-$terms.
$\var{simplify(expression("x^2-2*"+Cx+"*x"),"all")} = (x + $
$\var{simplify(expression("y^2-2*"+Cy+"*y"),"all")} = (y + $
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