larger truth table

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Bernhard von Stengel

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Bernhard von Stengel 8 years, 6 months ago

Created this as a copy of Truth tables 1(v2).

Name	Status	Author	Last Modified
Truth tables 1(v2)	Ready to use	Newcastle University Mathematics and Statistics	20/11/2019 14:51
Bernhard's copy of Truth tables 1(v2)	draft	Bernhard von Stengel	14/10/2016 23:40
larger truth table	draft	Bernhard von Stengel	28/09/2016 19:13
truth table with 3 logic variables	Ready to use	Bernhard von Stengel	30/09/2022 16:37
why parentheses are important for implication	draft	Bernhard von Stengel	30/09/2017 22:05
Daniel's copy of Truth tables 1(v2)	draft	Daniel Mansfield	29/08/2017 02:37
Truth tables 1	draft	Marie Nicholson	04/02/2021 15:25
Marie's copy of truth table with 3 logic variables	draft	Marie Nicholson	04/02/2021 15:25
Marie's copy of larger truth table	draft	Marie Nicholson	04/02/2021 15:25
Luis's copy of Truth tables 1(v2)	draft	Luis Hernandez	30/11/2018 00:55
Luis's copy of Truth tables 1(v2)	draft	Luis Hernandez	30/11/2018 00:56
Construir la tabla de verdad para una proposición compuesta....	Ready to use	Luis Hernandez	06/06/2023 01:11
Construir una tablas de verdad para una proposición compuesta (1)	draft	Luis Hernandez	02/12/2020 15:42
Jordan's copy of Truth tables 1(v2)	draft	Jordan Childs	10/07/2019 15:23

There are 18 other versions that do you not have access to.

Question statement

In this question you are asked to construct a truth table for the expressions

$p\Rightarrow(q\wedge r)$ and $(p\Rightarrow q)\wedge (p\Rightarrow r)$ , using all possible combinations of truth values for $p,q,r$ .

Recall that $0$ means false and $1$ means true.

Give any introductory information the student needs.

			Name	Type	Generated Value

Automatically regenerate variables?

No variables have been defined in this question.

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Part a) Gap-fill
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Part b) Choose one from a list

Gap-fill

Ask the student a question, and give any hints about how they should answer this part.

Complete the following truth table; enter $0$ for false and $1$ for true.

$p$	$q$	$r$	$q\land r$	$p\Rightarrow(q\land r)$	$p\Rightarrow q$	$p\Rightarrow r$	$(p\Rightarrow q)\land(p\Rightarrow r)$
0	0	0	Gap 0.	Gap 8.	Gap 16.	Gap 24.	Gap 32.
0	0	1	Gap 1.	Gap 9.	Gap 17.	Gap 25.	Gap 33.
0	1	0	Gap 2.	Gap 10.	Gap 18.	Gap 26.	Gap 34.
0	1	1	Gap 3.	Gap 11.	Gap 19.	Gap 27.	Gap 35.
1	0	0	Gap 4.	Gap 12.	Gap 20.	Gap 28.	Gap 36.
1	0	1	Gap 5.	Gap 13.	Gap 21.	Gap 29.	Gap 37.
1	1	0	Gap 6.	Gap 14.	Gap 22.	Gap 30.	Gap 38.
1	1	1	Gap 7.	Gap 15.	Gap 23.	Gap 31.	Gap 39.

Advice

Use the truth tables for the "and" operator $\wedge$ and the implication $\Rightarrow$ . Remember that $p\Rightarrow q$ is true whenever $p$ is false or $q$ is true.

Give a worked solution to the whole question.

Use this tab to check that this question works as expected.

There was an error which means the tests can't run:

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Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

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Checkpoint description

Bernhard von Stengel 8 years, 6 months ago

Error in variable testing condition

Parts

Gap-fill