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Basic calculation exercise using distance in km, expected mph and desired arrival time (with the conversion factor for km to miles given).
Based on a generic test QTS question.
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
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From users who are members of Headstart :
| Rob Cade | said | Ready to use | 8 years, 10 months ago |
History
Rob Cade 8 years, 10 months ago
Published this.Rob Cade 8 years, 10 months ago
Gave some feedback: Ready to use
Rob Cade 11 years, 7 months ago
Created this as a copy of Cost for a journey.| Name | Status | Author | Last Modified | |
|---|---|---|---|---|
| Cost for a journey | Ready to use | Rob Cade | 02/09/2016 13:33 | |
| Time for a journey | Ready to use | Rob Cade | 17/06/2016 12:34 |
| Name | Type | Generated Value |
|---|
| durationminutes | rational |
150
|
||||
| endtimehours | integer |
12
|
||||
| anstotalminutes | rational |
620
|
||||
| endtimeminutes | integer |
50
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||||
| endtimestring | string |
12:50
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| mph | integer |
50
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||||
| ansminutes | decimal |
dec("20")
|
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| ansstring | string |
10:20
|
||||
| distancekm | integer |
200
|
||||
| anshours | integer |
10
|
||||
| kmpermile | rational |
8/5
|
Generated value: rational
This variable doesn't seem to be used anywhere.
Gap-fill
Ask the student a question, and give any hints about how they should answer this part.
You're planning a journey of {distanceKm} km and you want to arrive no later than {endTimeString}
You reckon your average speed will be {mph} mph.
If 5 miles is about 8 km, what's the latest you should leave? Please give your answer in 24-hour clock format (HH:mm)
Answer: you should leave no later than
Use this tab to check that this question works as expected.
| Part | Test | Passed? |
|---|---|---|
| Gap-fill | ||
| Hasn't run yet | ||
| Match text pattern | ||
| Hasn't run yet | ||
| Information only |
This question is used in the following exams: