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Metadata
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
Contributors
History
Julie Crowley 8 years, 4 months ago
Created this as a copy of Q1 Indices in their simplest form 1.Name | Status | Author | Last Modified | |
---|---|---|---|---|
Q1 Indices in their simplest form 1 | draft | TEAME CIT | 08/10/2016 22:19 | |
Q1(a) Indices in their simplest form 1 | draft | Julie Crowley | 08/11/2016 17:03 | |
Q1(b) Indices in their simplest form 1 | draft | Julie Crowley | 08/11/2016 17:01 | |
Julie's copy of Q1(b) Indices in their simplest form 1 | draft | Julie Crowley | 15/11/2016 15:34 |
There are 4 other versions that do you not have access to.
Name | Type | Generated Value |
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num11 | list |
[ 4, 3 ]
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num12 | list |
[ 3, 4 ]
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ans11a | decimal |
dec("81")
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ans12a | decimal |
dec("8")
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ans13a | decimal |
dec("8")
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ans14a | decimal |
dec("256")
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ans11 | decimal |
dec("3")
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ans12 | decimal |
dec("8")
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ans13 | decimal |
dec("1.99999999999999861370563888010986161855")
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ans14 | decimal |
dec("256")
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num21 | list |
[ 3, 4, 5, 2 ]
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num22 | integer |
14
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ans21 | number |
7
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ans22 | number |
-11
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num23 | list |
[ 2, 5, 6, 7, 3, 4 ]
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ans23a | number |
-9
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ans23b | number |
8
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ans23c | number |
10
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ans24a | integer |
3
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num24a | number |
27
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ans24b | integer |
1
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ans24c | integer |
-4
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num24b | integer |
3
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num24c | integer |
-12
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num25 | list |
[ 3, 4, 2 ]
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num25a | integer |
2
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ans25a | decimal |
dec("4")
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ans25b | number |
-6
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ans25c | number |
8
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ans25d | number |
2
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num26a | list |
[ 2, 4, 5 ]
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num26b | list |
[ 2, 4, 5, 3 ]
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ans26a | number |
-14
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ans26b | number |
7
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ans26c | number |
-1
|
Generated value: list
- ans11
- ans11a
- ans12
- ans13
- ans13a
- ans14
This variable doesn't seem to be used anywhere.
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Ask the student a question, and give any hints about how they should answer this part.
Simplify each of the following, without using a calculator:
i) x{num21[0]}.x{num21[1]}
x^{
ii) x{num21[2]}.x−{num21[3]}x{num22}
x^{
iii) a−{num23[0]}.b{num23[1]}.c{num23[2]}a{num23[3]}.b−{num23[4]}.c−{num23[5]}
(a^{
iv) ({num24a}x{num24b}y{num24c})13
v) ({num25a}a−{num25[0]}b{num25[1]}c){num25[2]}
vi) 2{num26a[0]}.27{num26a[1]}.7{num26a[2]}4{num26b[0]}.8{num26b[1]}.3{num26b[2]}.49{num26b[3]}
(2^{
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