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A a 3×3 matrix. Using row operations on the augmented matrix (A|I3) reduce to (I3|A−1).
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History
Chris Saker was given access to the Hollie's copy of Invert a 3x3 matrix using row operations 8 years, 3 months ago
Hollie Tarr 8 years, 3 months ago
Created this as a copy of Invert a 3x3 matrix using row operations.Name | Status | Author | Last Modified | |
---|---|---|---|---|
Invert a 3x3 matrix using row operations | draft | Newcastle University Mathematics and Statistics | 20/11/2019 14:50 | |
Hollie's copy of Invert a 3x3 matrix using row operations | draft | Hollie Tarr | 01/12/2016 12:33 | |
Hollie's copy of Invert a 3x3 matrix using row operations | draft | Hollie Tarr | 22/02/2017 14:22 | |
Harry's copy of Invert a 3x3 matrix using row operations | draft | Harry Flynn | 09/03/2018 14:46 | |
Maria's copy of Invert a 3x3 matrix using row operations | draft | Maria Aneiros | 23/05/2019 07:00 | |
Simon's copy of Invert a 3x3 matrix using row operations | draft | Simon Thomas | 12/06/2019 13:51 |
There are 18 other versions that do you not have access to.
Name | Type | Generated Value |
---|
a | integer |
3
|
||||
a11 | integer |
1
|
||||
a12 | integer |
4
|
||||
a13 | integer |
-8
|
||||
a21 | integer |
-3
|
||||
a22 | integer |
-11
|
||||
a23 | number |
21
|
||||
a31 | integer |
-3
|
||||
a32 | integer |
-4
|
||||
a33 | integer |
1
|
||||
b | integer |
4
|
||||
b24 | integer |
-60
|
||||
b25 | integer |
-23
|
||||
c | integer |
1
|
||||
c1 | integer |
2
|
||||
c2 | integer |
3
|
||||
c3 | integer |
2
|
||||
f1 | integer |
1
|
||||
f2 | integer |
-1
|
||||
f3 | integer |
-1
|
||||
g1 | integer |
1
|
||||
g2 | integer |
1
|
||||
g3 | integer |
-1
|
||||
s | integer |
-1
|
Generated value: integer
3
→ Used by:
- a13
- a21
- a22
- a23
- a31
- b24
- b25
- "Part a)" → "Gap 3." - Minimum accepted value
- "Part a)" → "Gap 3." - Maximum accepted value
- "Part a)" → "Gap 4." - Minimum accepted value
- "Part a)" → "Gap 4." - Maximum accepted value
- "Part b)" → "Gap 0." - Minimum accepted value
- "Part b)" → "Gap 0." - Maximum accepted value
- "Part b)" → "Gap 1." - Minimum accepted value
- "Part b)" → "Gap 1." - Maximum accepted value
- "Part b)" → "Gap 2." - Minimum accepted value
- "Part b)" → "Gap 2." - Maximum accepted value
- "Part b)" → "Gap 5." - Minimum accepted value
- "Part b)" → "Gap 5." - Maximum accepted value
- "Part c)" → "Gap 2." - Minimum accepted value
- "Part c)" → "Gap 2." - Maximum accepted value
- "Part c)" → "Gap 3." - Minimum accepted value
- "Part c)" → "Gap 3." - Maximum accepted value
- "Part c)" → "Gap 8." - Minimum accepted value
- "Part c)" → "Gap 8." - Maximum accepted value
Parts
Gap-fill
Ask the student a question, and give any hints about how they should answer this part.
Part 1.
Introduce zeros in the first column below the first entry by adding suitable multiples of the first row to rows 2 and 3.
Input all numbers as fractions or integers and not as decimals.
(.... |
{a11} | {a12} | {a13} | 1 | 0 | 0 | ).... |
0 | 1 | 0 | |||||
0 | 0 | 1 |
Now, if necessary, multiply the second row by a suitable number so that the second entry in the second row is 1.
Use this tab to check that this question works as expected.
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This question is used in the following exams: