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Seibu Mary's copy of Algebra VIII: solving simultaneous equations (by elimination)
Straightforward solving linear equations question.
Adapted from 'Simultaneous equations by elimination 1 with parts' by Joshua Boddy.
Metadata
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
Contributors
History
Seibu Mary Jacob 8 years, 2 months ago
Created this as a copy of Algebra VIII: solving simultaneous equations (by elimination).There are 32 other versions that do you not have access to.
Name | Type | Generated Value |
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a | integer |
-6
|
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b | integer |
-4
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ans1 | integer |
36
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ans2 | integer |
-26
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ans3 | integer |
-152
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yCoef | integer |
38
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||||
n1 | integer |
-10
|
||||
n2 | integer |
6
|
||||
n3 | integer |
3
|
||||
n4 | integer |
2
|
Generated value: integer
- ans1
- ans2
- b
- Advice
- "Part e)" → "Unnamed gap" - Correct answer
Parts
Gap-fill
Ask the student a question, and give any hints about how they should answer this part.
We are going to solve for y first. To do this, we need to eliminate x from the equations. The quickest way to do this is to multiply the first equation by the co-efficient of x in the second equation (here {n3}), and multiply the second equation by the co-efficient of x in the first equation (here {n1}). We then get the equations:
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