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Customised for the Numbas demo exam
Motion under gravity. Object is projected vertically with initial velocity Vm/s. Find time to maximum height and the maximum height. Now includes an interactive plot.
Metadata
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
Contributors
History
Harry Flynn 8 years ago
Created this as a copy of Numbas demo: Motion under gravity.Name | Status | Author | Last Modified | |
---|---|---|---|---|
Numbas demo: Motion under gravity | Ready to use | Christian Lawson-Perfect | 05/10/2021 10:04 | |
Liz's copy of Numbas demo: Motion under gravity | draft | Liz Thompson | 03/02/2021 13:59 | |
Ethan's copy of Numbas demo: Motion under gravity | draft | Ethan Smith | 03/02/2021 13:59 | |
Harry's copy of Numbas demo: Motion under gravity | draft | Harry Flynn | 03/02/2021 13:59 | |
Santa's elves equation of a straight line | Needs to be tested | Chris Graham | 03/02/2021 13:59 | |
Numbas demo: Motion under gravity | draft | Xiaodan Leng | 03/02/2021 13:59 | |
Alan's copy of Numbas demo: Motion under gravity | draft | Alan Levine | 03/02/2021 13:59 | |
Numbas demo: Images, videos and interactive diagrams | Ready to use | Christian Lawson-Perfect | 24/08/2023 08:17 | |
GEMIDDELD: Valbeweging van een balletje | draft | Alexander Holvoet | 02/06/2024 14:36 |
There are 30 other versions that do you not have access to.
Name | Type | Generated Value |
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t | number |
7.5433231397
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v | integer |
74
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mh | number |
279.10
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g | number |
9.81
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t1 | number |
7.54
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Generated value: number
- g
- v
- t1
Gap-fill
Ask the student a question, and give any hints about how they should answer this part.
{graphsolution()}
Input the vertical distance $z$ as a function of $t$.
Note that at $t=0$ we have $z=0$ and that $\displaystyle \frac{dz}{dt}=\var{v}m/s$.
Input gravitational acceleration as $g$.
$z=$
Your formula is plotted in the graph above. The vertical axis represents $z$ and the horizontal axis represents $t$.
Note that the blue line indicates that:
- Your solution should go through $(0,0)$;
- Your solution should have this line as the tangent to the curve at $(0,0)$, because $\displaystyle \frac{\mathrm{d}z}{\mathrm{d}t}=\var{v}\; m/s$.
Use this tab to check that this question works as expected.
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