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Christian LawsonPerfect 1 year, 10 months ago
Gave some feedback: Ready to use
Christian LawsonPerfect 1 year, 10 months ago
Saved a checkpoint:
You're right! I've fixed it, and improved the TeX. Worried that I let that slip by!
Deirdre Casey 1 year, 10 months ago
Gave some feedback: Has some problems
Deirdre Casey 1 year, 10 months ago
I think there is a sign error in the second equation in part b.
Christian LawsonPerfect 2 years, 1 month ago
Gave some feedback: Ready to use
Christian LawsonPerfect 2 years, 1 month ago
Saved a checkpoint:
Set up the randomisation again so that all numbers are integers.
In part a, the $x$ coefficient of the second equation is a multiple of the coefficient in the first equation.
In part b, the LCMs of the $x$ and $y$ coefficients are strictly larger than any of the coefficients.
Elliott Fletcher 2 years, 2 months ago
Published this.Lauren Richards 2 years, 2 months ago
Gave some feedback: Needs to be tested
Lauren Richards 2 years, 2 months ago
 I've made sure that the solutions are integers but that has meant that the question is not randomised.
 I'm also having a little trouble in centering a section of part a) which includes an overline and a subtraction.
 Otherwise, I've made all the changes you requested.
Christian LawsonPerfect 2 years, 2 months ago
Gave some feedback: Has some problems
Christian LawsonPerfect 2 years, 2 months ago
Saved a checkpoint:
I'd prefer it if you made sure that the solutions are always integers. Rounding errors are a distraction here. Generate the solutions first, then come up with a pair of independent equations.
I'm not sure about the way you've set out subtracting one equation from another  it's not obvious that the minus signs cancel out when there's a negative coefficient. This is one of the big problems that trips people up when doing this.
Be careful with, for example, "We have to multiply the entire first equation by 3, not just the x term to ensure we do not change the value of the equation."  an equation doesn't have a 'value'. You could instead say that you want to keep the same solution.
Right at the end of the advice, I don't like $8(5)$ for multiplication  $8 \times 5$ is much more conventional.
Lauren Richards 2 years, 2 months ago
Gave some feedback: Needs to be tested
Lauren Richards 2 years, 2 months ago
It won't let me put visibility conditions on it. :(
Lauren Richards 2 years, 2 months ago
Created this.No variables have been defined in this question.
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