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From users who are members of Transition to university :
|Christian Lawson-Perfect||said||Ready to use||4 years, 2 months ago|
|Lauren Richards||said||Needs to be tested||4 years, 6 months ago|
From users who are not members of Transition to university :
|Deirdre Casey||said||Has some problems||4 years, 2 months ago|
Christian Lawson-Perfect 4 years, 6 months ago
Saved a checkpoint:
Set up the randomisation again so that all numbers are integers.
In part a, the $x$ coefficient of the second equation is a multiple of the coefficient in the first equation.
In part b, the LCMs of the $x$ and $y$ coefficients are strictly larger than any of the coefficients.
Lauren Richards commented 4 years, 6 months ago
- I've made sure that the solutions are integers but that has meant that the question is not randomised.
- I'm also having a little trouble in centering a section of part a) which includes an overline and a subtraction.
- Otherwise, I've made all the changes you requested.
Christian Lawson-Perfect 4 years, 6 months ago
Saved a checkpoint:
I'd prefer it if you made sure that the solutions are always integers. Rounding errors are a distraction here. Generate the solutions first, then come up with a pair of independent equations.
I'm not sure about the way you've set out subtracting one equation from another - it's not obvious that the minus signs cancel out when there's a negative coefficient. This is one of the big problems that trips people up when doing this.
Be careful with, for example, "We have to multiply the entire first equation by 3, not just the x term to ensure we do not change the value of the equation." - an equation doesn't have a 'value'. You could instead say that you want to keep the same solution.
Right at the end of the advice, I don't like $8(5)$ for multiplication - $8 \times 5$ is much more conventional.
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