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Metadata
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
Contributors
History
Johan Maertens 7 years, 5 months ago
Created this as a copy of Volgorde met natuurlijke getallen.Name | Status | Author | Last Modified | |
---|---|---|---|---|
Q1 Arithmetic | draft | TEAME CIT | 07/10/2016 23:15 | |
David's copy of Q1 Arithmetic | draft | David Rickard | 08/10/2016 17:25 | |
Volgorde met natuurlijke getallen | draft | Johan Maertens | 13/09/2017 20:38 | |
Volgorde met gehele getallen | draft | Johan Maertens | 04/02/2024 16:31 |
There are 2 other versions that do you not have access to.
Name | Type | Generated Value |
---|
numberlow | list |
List of 12 items
|
||||
ans1 | number |
67
|
||||
ans2 | number |
144
|
||||
num3a | number |
50
|
||||
numberhigh | integer |
20
|
||||
num3b | number |
70
|
||||
ans3 | number |
80
|
||||
ans4 | number |
46
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||||
ans5 | number |
32
|
||||
ans6 | number |
-492
|
||||
numsq | list |
[ -4, -6 ]
|
||||
numsq1 | number |
40
|
||||
ans7 | number |
22
|
||||
numsq2 | list |
[ -3, -5 ]
|
||||
ans8 | number |
1
|
||||
numsq3 | number |
48
|
||||
ans9 | number |
-6
|
||||
numsq4 | number |
16
|
||||
ans10 | number |
-76
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||||
kwadraat | integer |
400
|
||||
ngeh1 | integer |
-2
|
||||
ngeh2 | integer |
-10
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||||
ngeh3 | integer |
-4
|
||||
ans11 | number |
-18
|
Generated value: list
- ans1
- ans10
- ans2
- ans3
- ans4
- ans5
- ans6
- ans7
- ans9
- num3a
- numsq1
- numsq3
- numsq4
- Advice
- "Reken uit met de volgorde van bewerkingen" - prompt
Parts
Gap-fill
Ask the student a question, and give any hints about how they should answer this part.
a) ({numberlow[0]})⋅({numberlow[1]})+({numberlow[2]})=
b) {numberlow[7]}⋅[({numberlow[3]})+({numberlow[6]})]=
c) {num3b}−{num3a}÷({numberlow[5]})=
d) {numberlow[8]}+({numberlow[4]})⋅({numberlow[3]}+{numsq[0]})=
e)[({numberlow[1]})+({numberlow[7]})]⋅({numberlow[8]})+{numsq[1]}=
f) {numberlow[6]}+{numsq[0]}⋅({numberlow[0]})2=
g) ({numberlow[4]})⋅({numberlow[9]})−({numsq1})÷({numberlow[2]})=
h) [({numsq2[1]})−({numsq[1]})]2=
i) [{numsq2[0]}−({numsq[0]})]2⋅{numsq3}÷({numberlow[6]})=
j) {numsq2[1]}⋅({numsq[0]})2−{numsq4}÷({numberlow[3]})=
k) −√{kwadraat}+({ngeh1})⋅({ngeh2})0−({ngeh3})=
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This question is used in the following exams: