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Ready to use

6 years, 10 months ago

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Sean Gardiner 6 years, 10 months ago

Published this.

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Sean Gardiner 6 years, 10 months ago

Gave some feedback: Ready to use

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Sean Gardiner 6 years, 10 months ago

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Name	Status	Author	Last Modified
RAW demo	Ready to use	Sean Gardiner	11/07/2019 02:18
RAW demo 1	draft	Sean Gardiner	21/05/2019 03:28
RAW demo	draft	Xiaodan Leng	10/07/2019 23:59

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Question statement

This question is about manipulating linear and quadratic functions.

(You could also use this section to provide any formulae the students might want to reference.)

(Or it could be the main, referenced part of a multi-part question.)

Give any introductory information the student needs.

			Name	Type	Generated Value

x0	integer	4
a	integer	-3
b	integer	2

			Name	Type	Generated Value

a2	integer	-2
b2	integer	3
c2	integer	2
name	string	Jessica

			Name	Type	Generated Value

r	integer	-6
s	integer	7
b3	integer	-1
c3	integer	-42

			Name	Type	Generated Value

Automatically regenerate variables?

Name

Data type

Value

A random number between and (inclusive) with step size

Description

This is the value for x which is substituted in part 1.

Describe what this variable represents, and list any assumptions made about its value.

Can an exam override the value of this variable?

Generated value: `integer`

→ Used by:

Advice
"Part a)" - prompt
"Part a)" - Minimum accepted value
"Part a)" - Maximum accepted value

Advice

When evaluating a function $f(x)$ at a point $x=\var{x0}$ , simply substitute $x$ in the expression with the value $\var{x0}$ .

When differentiating a polynomial with respect to $x$ , take each term $a_n x^n$ and multiply its coefficient by $n$ before reducing its power by 1, giving $n a_n x^{n-1}$ .

To find the roots of a quadratic, you might be able to do it by sight by noting that the sum of the two roots should be the negative of the coefficient of $x$ , while the product of the two roots should be the constant term. This is explained in more detail in the expanded part above.

Otherwise, you can always find the root(s) of a general quadratic $a x^2 + b x + c = 0$ by using the quadratic formula:

$r = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

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Taxonomy: mathcentre

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Checkpoint description

Sean Gardiner 6 years, 10 months ago

Sean Gardiner 6 years, 10 months ago

Sean Gardiner 6 years, 10 months ago

Error in variable testing condition

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Generated value: `integer`

Parts

Number entry

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RAW demo

Metadata

Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

Contributors

Feedback

History

Comment

Checkpoint description

Sean Gardiner 6 years, 10 months ago

Sean Gardiner 6 years, 10 months ago

Sean Gardiner 6 years, 10 months ago

Error in variable testing condition

Error

Warning

Generated value: integer

Parts

Number entry

Advanced settings

Generated value: `integer`