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Find the reactions of a rigid body (a triangular plate) at a pin and roller, using the three-force body principle.
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
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From users who are members of Engineering Statics :
William Haynes
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said | Ready to use | 5 years, 9 months ago |
History
William Haynes 5 years, 9 months ago
Gave some feedback: Ready to use
William Haynes 5 years, 10 months ago
Gave some feedback: Needs to be tested
William Haynes 5 years, 10 months ago
Gave some feedback: Doesn't work
William Haynes 6 years, 6 months ago
Gave some feedback: Ready to use
William Haynes 6 years, 7 months ago
Gave some feedback: Needs to be tested
William Haynes 6 years, 7 months ago
Created this as a copy of Equilibrium of a rigid body: triangle.| Name | Status | Author | Last Modified | |
|---|---|---|---|---|
| Equilibrium of a rigid body: truss | Ready to use | William Haynes | 05/10/2023 15:32 | |
| Equilibrium of a rigid body: triangle | Ready to use | William Haynes | 01/04/2023 21:45 | |
| Three-force body method: triangle | Ready to use | William Haynes | 12/02/2024 19:19 | |
| Equilibrium of a three-force body: triangle | draft | Xiaodan Leng | 10/07/2019 21:37 |
There are 2 other versions that do you not have access to.
| Name | Type | Generated Value |
|---|
| theta | integer |
305
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| units | list |
[ "kN", "m" ]
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| alpha1 | integer |
60
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| FB | quantity |
quantity(20, "kN")
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| L | quantity |
quantity(4.4, "m")
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| Name | Type | Generated Value |
|---|
| debug | boolean |
false
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| h | quantity |
quantity(0.6685861618188764, "m")
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| theta_a | quantity |
quantity(8.640080890613477, "deg")
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| alpha | quantity |
quantity(35, "deg")
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| beta | quantity |
quantity(81.359919109386523, "deg")
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| gamma | quantity |
quantity(63.640080890613477, "deg")
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||||
| FA | quantity |
quantity(11.60320734678238118047833307013499865539, "kN")
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||||
| FC | quantity |
quantity(18.12615574073299476720632962977409955051, "kN")
|
Generated value: integer
- alpha
- h
- Statement
- Variable testing condition
- "Angles in Triangle" - prompt
Parts
Gap-fill
Ask the student a question, and give any hints about how they should answer this part.
A three-force body is an object acted upon by exactly three forces. When a three-force body is in equilibrium the lines of action of the three forces must either intersect at a common point or be parallel to each other. We can use this idea to find the reaction forces for three-force bodies.
In this problem the lines of action of force $\mathbf{B}$ and force $\mathbf{C}$ are known and their intersection point $X$ may be determined.
Use the given geometric information to determine distance $h$.
$h$ =
h = {h}
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This question is used in the following exams:
- Chapter 5 Exercises by William Haynes in Engineering Statics.
- Chapter 05 Exercises by Michael Proudman in Engineering Statics.
- 15. 2 and 3 Force Bodies by Michael Proudman in Engineering Statics.
- studio 4 - Chapter 5 Exercises by Jay McCormack in studio 4.
- studio 4 - Chapter 5 Exercises by Jay McCormack in Jay's workspace.
- 15. 2 and 3 Force Bodies by William Haynes in Engineering Statics.