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Straightforward solving linear equations question.
Adapted from 'Simultaneous equations by elimination 1 with parts' by Joshua Boddy.
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
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From users who are members of heike's workspace :
heike hoffmann | said | Ready to use | 6 years, 5 months ago |
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heike hoffmann 6 years, 5 months ago
Gave some feedback: Ready to use
heike hoffmann 6 years, 5 months ago
Created this as a copy of Algebra VIII: solving simultaneous equations (by elimination).There are 32 other versions that do you not have access to.
Name | Type | Generated Value |
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a | integer |
5
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||||
b | integer |
3
|
||||
ans1 | integer |
-60
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||||
ans2 | integer |
-23
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||||
ans3 | integer |
213
|
||||
yCoef | integer |
71
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||||
n1 | integer |
-9
|
||||
n2 | integer |
-5
|
||||
n3 | integer |
-7
|
||||
n4 | integer |
4
|
Generated value: integer
- ans1
- ans2
- b
- Advice
- "Part e)" → "Unnamed gap" - Correct answer
Parts
Gap-fill
Ask the student a question, and give any hints about how they should answer this part.
We are going to solve for y first. To do this, we need to eliminate x from the equations. The quickest way to do this is to multiply the first equation by the co-efficient of x in the second equation (here {n3}), and multiply the second equation by the co-efficient of x in the first equation (here {n1}). We then get the equations:
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This question is used in the following exam: