Simon's copy of Q5 Oil tanks problems

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Simon Thomas 6 years, 1 month ago

Created this as a copy of Q5 Oil tanks problems.

Name	Status	Author	Last Modified
Q5 Oil tanks problems	draft	TEAME CIT	07/10/2016 10:16
Simon's copy of Q5 Oil tanks problems	draft	Simon Thomas	21/02/2019 11:05

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Question statement

Solve the following oil tank questions to the nearest pound.

Give any introductory information the student needs.

			Name	Type	Generated Value

size	list	[ 3.04, 3.09, 2.84, 3.52 ]
dia	list	[ 1.57, 1.5 ]
per	list	[ 80, 70 ]
price	list	[ 76.2, 89.1, 88.3 ]
vol1	number	1.6448248161
dia1	integer	830
ans1	number	1002.6852078849
vol2	number	5.9820173128
ans2	number	5329.9774257417
vol3	number	14.9952
ans3	number	13240.7616

Automatically regenerate variables?

Name

Data type

Value

xxxxxxxxxx
 
shuffle(2.6..3.75#0.01)[0..4]

JME function reference

Description

Describe what this variable represents, and list any assumptions made about its value.

Can an exam override the value of this variable?

Generated value: `list`

[ 3.04, 3.09, 2.84, 3.52 ]

→ Used by:

vol1
vol2
vol3

Advice
"Part a)" - prompt
"Part b)" - prompt
"Part c)" - prompt

Parts

Part a) Gap-fill
1. Gap Number entry
  Add
1. Step Information only
Part b) Gap-fill
1. Gap Number entry
  Add
Part c) Gap-fill
1. Gap Number entry
  Add

Gap-fill

Ask the student a question, and give any hints about how they should answer this part.

A rectangular oil tank has dimensions $\var{size[2]}$ m by $\var{size[3]}$ m by $\var{dia[1]}$ m. Find the cost to fill this tank if the fuel is priced at $\var{price[2]}$ pence per litre.

£Unnamed gap

Advice

N.B

1 m = 1000 mm

1 m $^3$ = 1000 litres

(a)

V = length $\times$ breadth $\times$ height

V = $\var{size[2]} \times \var{size[3]} \times \var{dia[1]} = \var{precround(vol3,3)}$ m $^3$ (which we convert to litres by $\times 1000$ )

Ans = $\var{precround(vol3,3)} \times 1000 \times (\frac{\var{price[2]}}{100}) = £\var{precround(ans3,0)}$

(b)

Volume of cylindrical oil tank

V = $\pi r^2h$

V = $\pi \times(\frac{\var{dia[0]}}{2})^2 \times \var{size[1]} = \var{precround(vol2,3)}$ m $^3$ (which we convert to litres by $\times 1000$ )

Ans = $\var{precround(vol2,3)} \times 1000 \times (\frac{\var{price[1]}}{100}) = £\var{precround(ans2,0)}$

(c)

Volume of cylindrical oil tank

V = $\pi r^2h$

Remember to convert from mm to m by dividing the diameter by 1000:

V = $\pi \times(\frac{\var{dia1}}{2\times1000})^2 \times \var{size[0]} = \var{precround(vol1,3)}$ m $^3$ (which we convert to litres by $\times 1000$ )

Ans = $\var{precround(vol1,3)} \times 1000 \times (\frac{\var{price[0]}}{100}) \times (\frac{\var{per[0]}}{100}) = £\var{precround(ans1,0)}$

Give a worked solution to the whole question.

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This question is used in the following exam:

Mensuration by Simon Thomas in Maths support.

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Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

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Simon Thomas 6 years, 1 month ago

Error in variable testing condition

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Warning

Generated value: `list`

Parts

Gap-fill

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Simon's copy of Q5 Oil tanks problems

Metadata

Taxonomy: mathcentre

Taxonomy: Kind of activity

Taxonomy: Context

Contributors

History

Comment

Checkpoint description

Simon Thomas 6 years, 1 month ago

Error in variable testing condition

Error

Warning

Generated value: list

Parts

Gap-fill

Generated value: `list`