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Find the reactions of a rigid body (a triangular plate) at a pin and roller, using the three-force body principle.
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
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History
Xiaodan Leng 5 years, 8 months ago
Created this as a copy of Three-force body method: triangle.| Name | Status | Author | Last Modified | |
|---|---|---|---|---|
| Equilibrium of a rigid body: truss | Ready to use | William Haynes | 05/10/2023 15:32 | |
| Equilibrium of a rigid body: triangle | Ready to use | William Haynes | 01/04/2023 21:45 | |
| Three-force body method: triangle | Ready to use | William Haynes | 12/02/2024 19:19 | |
| Equilibrium of a three-force body: triangle | draft | Xiaodan Leng | 10/07/2019 21:37 |
There are 2 other versions that do you not have access to.
| Name | Type | Generated Value |
|---|
| theta | integer |
325
|
||||
| units | list |
[ "lb", "in" ]
|
||||
| alpha1 | integer |
50
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||||
| FB | quantity |
quantity(300, "lbs")
|
||||
| L | quantity |
quantity(5.6, "in")
|
| Name | Type | Generated Value |
|---|
| debug | boolean |
false
|
||||
| h | quantity |
quantity(1.3763289522766, "in")
|
||||
| theta_a | quantity |
quantity(13.808076375425182, "deg")
|
||||
| alpha | quantity |
quantity(55, "deg")
|
||||
| beta | quantity |
quantity(76.191923624574818, "deg")
|
||||
| gamma | quantity |
quantity(48.808076375425182, "deg")
|
||||
| FA | quantity |
quantity(253.058850399366616889741540341980470257, "lbs")
|
||||
| FC | quantity |
quantity(232.4705742020014966069846661911002007552, "lbs")
|
Generated value: integer
This variable doesn't seem to be used anywhere.
Gap-fill
Ask the student a question, and give any hints about how they should answer this part.
A three-force body is an object acted upon by exactly three forces. When a three-force body is in equilibrium the lines of action of the three forces must either intersect at a common point or be parallel to each other. We can use this idea to find the reaction forces for three-force bodies.
In this problem the lines of action of force B and force C are known and their intersection point X may be determined.
Use the given geometric information to determine distance h.
h =
h = {h}
Use this tab to check that this question works as expected.
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