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There is only one version of this question that you have access to.
| Name | Type | Generated Value |
|---|
| powera | number |
0.5
|
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| v0 | expression |
"M"
|
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| v1 | expression |
"s"
|
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| qa | expression |
"M"=C*"s"^gamma
|
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| grada | number |
0.5
|
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| intercepta | number |
2.8
|
||||
| ca | number |
16
|
||||
| ansa | expression |
gamma*x + ln(C)
|
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| ansa2 | expression |
16*"s"^0.5
|
| Name | Type | Generated Value |
|---|
| v2 | expression |
"K"
|
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| v3 | expression |
"q"
|
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| qb | expression |
"K"=A*e^(B*"q")
|
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| gradb | rational |
-42/5
|
||||
| interceptb | number |
3.1
|
||||
| A | number |
22
|
||||
| ansb | expression |
B*x + ln(A)
|
||||
| ansb2 | expression |
22*e^((-42/5)*"q")
|
| Name | Type | Generated Value |
|---|
| vari | list |
List of 10 items
|
Generated value: number
This variable doesn't seem to be used anywhere.
Gap-fill
Ask the student a question, and give any hints about how they should answer this part.
We are investigating the relationship between the variables {{v0}} and {{v1}} experimentally.
We know that they are related via the equation {{qa}}, where γ and C are constants to be determined.
This is done by plotting {y=ln({v0})} against {x=ln({v1})}; we should get a straight line.
1. Write y in terms of x, γ and C. To enter "γ" you type "gamma". Use * to indicate multiplication.
y=
2. (Calculator). When plotting y against x, we get a straight line with gradient {{grada}} and y-intercept {intercepta}. Hence write {{v0}} in terms of {{v1}}. C should be provided to 2 s.f..
{{v0}}=
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