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Finding the coordinates and determining the nature of the stationary points on a polynomial function
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
History
Musa Mammadov 1 year, 8 months ago
Published this.Musa Mammadov 4 years, 8 months ago
Created this as a copy of Musa's copy of 3 Find coordinates of stationary points of polynomials.| Name | Status | Author | Last Modified | |
|---|---|---|---|---|
| Find coordinates of stationary points of polynomials | draft | Newcastle University Mathematics and Statistics | 20/11/2019 14:50 | |
| Luis's copy of Find coordinates of stationary points of polynomials | draft | Luis Hernandez | 30/11/2018 18:51 | |
| Musa's copy of 3 Find coordinates of stationary points of polynomials | draft | Musa Mammadov | 27/06/2023 01:35 | |
| Musa's copy of 5 Find coordinates of stationary points of polynomials | draft | Musa Mammadov | 20/07/2023 01:39 |
There are 12 other versions that do you not have access to.
| Name | Type | Generated Value |
|---|
| y1 | number |
41
|
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| y0 | integer |
9
|
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| y3 | number |
41
|
||||
| y2 | number |
49
|
||||
| y4 | number |
49
|
||||
| y02 | integer |
-4
|
||||
| y03 | integer |
-7
|
||||
| x1 | integer |
3
|
||||
| x43 | integer |
0
|
||||
| x42 | integer |
-2
|
||||
| y42 | number |
-4
|
||||
| y43 | number |
15.5
|
||||
| x03 | integer |
-3
|
||||
| x02 | integer |
-2
|
||||
| y22 | number |
-4
|
||||
| y23 | number |
11
|
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| x23 | integer |
3
|
||||
| x22 | integer |
-2
|
||||
| x2 | integer |
1
|
||||
| x3 | integer |
3
|
||||
| x0 | integer |
-1
|
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| c0 | number |
41
|
||||
| c02 | number |
-12
|
||||
| x4 | integer |
1
|
||||
| x32 | integer |
0
|
||||
| x33 | integer |
3
|
||||
| x13 | integer |
0
|
||||
| y33 | number |
11
|
||||
| y32 | number |
-12
|
||||
| x12 | integer |
0
|
||||
| c03 | number |
15.5
|
||||
| y13 | number |
15.5
|
||||
| y12 | number |
-12
|
||||
| x111 | integer |
-2
|
||||
| x222 | integer |
0
|
Generated value: number
This variable doesn't seem to be used anywhere.
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For the following function:
{y=2x3−3{x12+x22}x2+6{x12x22}x+{c02}}
Determine the coordinates and the nature of the stationary points.
First Derivative; y′(x)=
Give values of x where stationary points occur: smallest-x1 =
Second Derivative is y′′(x)=
Values of Second derivative at stationary points:
y′′(x1)=
y′′(x2)=
Minimum point: (
Enter fractions in their simplest form.
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