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Gaussian elimination to solve a system of linear equations - Introductory
Solving a system of three linear equations in 3 unknowns using Gaussian Elimination (or Gauss-Jordan algorithm) in 5 stages. Solutions are all integers. Introductory question where the numbers come out quite nice with not much dividing. Set-up is meant for formative assessment. Adapated from a question copied from Newcastle.
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
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From users who are members of Linear Algebra 1st year :
Tatiana Tyukina | said | Ready to use | 4 years, 8 months ago |
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said | Needs to be tested | 4 years, 8 months ago |
History
Julia Goedecke 4 years, 8 months ago
Published this.Tatiana Tyukina 4 years, 8 months ago
Gave some feedback: Ready to use
Julia Goedecke commented 4 years, 8 months ago
Combined the last two parts into one with some automatic fills of some of the gaps. Put the marks of the parts in.
Julia Goedecke 4 years, 8 months ago
Gave some feedback: Needs to be tested
Julia Goedecke 4 years, 8 months ago
Created this.Name | Status | Author | Last Modified | |
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Gaussian elimination to solve a system of linear equations - Introductory | Ready to use | Julia Goedecke | 25/08/2021 12:57 | |
Gaussian elimination to solve a system of linear equations - scaffolded | Ready to use | Julia Goedecke | 25/08/2021 12:57 | |
Gaussian elimination to solve a system of equations | Ready to use | Andrew Brown | 12/09/2022 14:48 | |
Gaussian elimination to solve a system of linear equations | Ready to use | Andrew Brown | 12/09/2022 14:48 |
There are 39 other versions that do you not have access to.
Name | Type | Generated Value |
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a | integer |
2
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c | integer |
1
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b | integer |
4
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c3 | integer |
1
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c2 | integer |
3
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y | number |
1
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x | number |
1
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c1 | integer |
5
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z | number |
-1
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Generated value: integer
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- Statement
- "Part a)" → "Gap 3." - Minimum accepted value
- "Part a)" → "Gap 3." - Maximum accepted value
- "Part a)" → "Gap 5." - Minimum accepted value
- "Part a)" → "Gap 5." - Maximum accepted value
- "Part a)" → "Gap 6." - Minimum accepted value
- "Part a)" → "Gap 6." - Maximum accepted value
- "Part a)" → "Gap 7." - Minimum accepted value
- "Part a)" → "Gap 7." - Maximum accepted value
- "Part a)" → "Gap 9." - Minimum accepted value
- "Part a)" → "Gap 9." - Maximum accepted value
- "Part b)" - prompt
- "Part b)" → "Gap 4." - Minimum accepted value
- "Part b)" → "Gap 4." - Maximum accepted value
- "Part b)" → "Gap 5." - Minimum accepted value
- "Part b)" → "Gap 5." - Maximum accepted value
- "Part b)" → "Gap 7." - Minimum accepted value
- "Part b)" → "Gap 7." - Maximum accepted value
- "Part c)" - prompt
- "Part c)" → "Gap 1." - Minimum accepted value
- "Part c)" → "Gap 1." - Maximum accepted value
- "Part c)" → "Gap 2." - Minimum accepted value
- "Part c)" → "Gap 2." - Maximum accepted value
- "Part c)" → "Gap 4." - Minimum accepted value
- "Part c)" → "Gap 4." - Maximum accepted value
- "Part d)" → "Gap 1." - Minimum accepted value
- "Part d)" → "Gap 1." - Maximum accepted value
- "Part d)" → "Gap 2." - Minimum accepted value
- "Part d)" → "Gap 2." - Maximum accepted value
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Gap-fill
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- Part b) Gap-fill
- Part c) Gap-fill
- Part d) Gap-fill
Gap-fill
Ask the student a question, and give any hints about how they should answer this part.
Re-arrange the rows so that the third row becomes the first row, the first the second and the second the third.
WHY? Choose one of the following:
Now write down the entries of the matrix you will use for Gaussian Elimination, remember to include the constants as the last column.
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