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Given two angles and a side-length of a triangle, use the sine rule to calculate an unknown side-length.
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
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From users who are members of MASH Bath: Question Bank :
| Ben McGovern | said | Ready to use | 3 years, 7 months ago |
History
Christian Lawson-Perfect 2 years, 6 months ago
Published this.Ben McGovern 3 years, 7 months ago
Gave some feedback: Ready to use
Ben McGovern 4 years, 6 months ago
Created this.| Name | Status | Author | Last Modified | |
|---|---|---|---|---|
| Trigonometry: Sine Rule 1 | Ready to use | Ben McGovern | 09/03/2023 09:50 | |
| Trigonometry: Sine Rule 2 | Ready to use | Ben McGovern | 10/10/2022 13:16 | |
| Trigonometry: Cosine Rule 1 | Ready to use | Ben McGovern | 09/03/2023 10:26 |
There are 34 other versions that do you not have access to.
| Name | Type | Generated Value |
|---|
| defs | list |
[ [ "C", vector(7,6) ] ]
|
||||
| A | vector |
vector(0,0)
|
||||
| B | vector |
vector(8,0)
|
||||
| C | vector |
vector(7,6)
|
||||
| sidea | number |
6.0827625303
|
||||
| sideb | number |
9.2195444573
|
||||
| anglea | number |
40.601294645
|
||||
| angleb | number |
80.537677792
|
||||
| sidear | number |
6.08
|
||||
| sidebr | number |
9.22
|
||||
| anglear | number |
40.60
|
||||
| anglebr | number |
80.54
|
||||
| bbb | number |
9.2156625211
|
||||
| bbbr | number |
9.22
|
Generated value: list
[ [ "C", vector(7,6) ] ]
← Depends on:
- C
→ Used by:
- Statement
- Advice
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| Gap-fill | ||
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