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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
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joshua boddy | said | Ready to use | 9 years, 7 months ago |
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joshua boddy 9 years, 7 months ago
Gave some feedback: Ready to use
joshua boddy 9 years, 8 months ago
Created this as a copy of Simultaneous equations by elimination 1.There are 32 other versions that do you not have access to.
Name | Type | Generated Value |
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a | integer |
2
|
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b | integer |
8
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||||
ans1 | integer |
8
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ans2 | integer |
56
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ans3 | integer |
256
|
||||
yCoef | integer |
32
|
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n1 | integer |
-4
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||||
n2 | integer |
2
|
||||
n3 | integer |
4
|
||||
n4 | integer |
6
|
Generated value: integer
This variable doesn't seem to be used anywhere.
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We are going to solve for y first. To do this, we need to eliminate x from the equations. The quickest way to do this is to multiply the first equation by the co-efficient of x in the second equation (here {n3}), and multiply the second equation by the co-efficient of x in the first equation (here {n1}). We then get the equations:
We then subtract one new equation from the other to get:
Now we can work out y
y=
and substitute this value back in to any of the previous equations to get the value for x.
which then solves to give x=
Use this tab to check that this question works as expected.
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