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This question tests the student's ability to solve Linear Programming problems by applying Geometric method.
Metadata
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England schools
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England university
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Scotland schools
Taxonomy: mathcentre
Taxonomy: Kind of activity
Taxonomy: Context
Contributors
History
Julien Ugon was given access to the SIT316 MO-Geometric Method-Q3 1 year, 8 months ago
Musa Mammadov 1 year, 8 months ago
Published this.Musa Mammadov 3 years, 8 months ago
Created this as a copy of SIT316 MO-Geometric Method-Q2.There are 88 other versions that do you not have access to.
| Name | Type | Generated Value |
|---|
| a1 | integer |
2
|
||||
| b1 | integer |
3
|
||||
| a2 | integer |
8
|
||||
| b2 | integer |
16
|
||||
| a3 | integer |
16
|
||||
| b3 | integer |
8
|
||||
| c11 | integer |
13
|
||||
| c12 | integer |
-6
|
||||
| c1 | integer |
8
|
||||
| c2 | integer |
-192
|
||||
| c3 | integer |
-32
|
||||
| c21 | integer |
-8
|
||||
| c22 | integer |
-8
|
||||
| c31 | integer |
5
|
||||
| c32 | integer |
-14
|
||||
| i | integer |
4
|
||||
| x22 | list |
[ 2, 2, 8, 16, 16 ]
|
||||
| x2 | integer |
16
|
||||
| y22 | list |
[ 0, 3, 16, 8, 0 ]
|
||||
| y2 | integer |
0
|
||||
| x1 | integer |
8
|
||||
| y1 | integer |
9
|
||||
| ox | integer |
-8
|
||||
| oy | integer |
9
|
||||
| f | list |
[ -16, 11, 80, -56, -128 ]
|
||||
| f1 | integer |
11
|
||||
| f0 | integer |
-16
|
||||
| f2 | integer |
80
|
||||
| f3 | integer |
-56
|
||||
| f4 | integer |
-128
|
||||
| f_sorted | vector |
vector(-128,-56,-16,11,80)
|
||||
| f11 | number |
-128
|
||||
| b2m | integer |
20
|
||||
| x11 | list |
[ 12, 12, 7, 7, 8 ]
|
||||
| y11 | list |
[ 5, 1, 2, 6, 9 ]
|
| Name | Type | Generated Value |
|---|
Generated value: integer
- c1
- c12
- c3
- c32
- f0
- f1
- x22
This variable doesn't seem to be used anywhere.
Gap-fill
Ask the student a question, and give any hints about how they should answer this part.
Solve the following Linear Programming problem by applying the geometric method.
Problem:
Minimize: {{ox}x+{oy}y}
subject to:
{−{c21}x−{c22}y≤−{c2}}
{−{c11}x−{c12}y≤−{c1}}
x≥{a1}
x≤{a3}
y≤{b2m}
x≥0
y≥0
The feasible region in this problem is a pentagon with 5 corners. Calculate objective function values at corner points and arrange them in assending order from smallest to largest as f1,f2,f3,f4,f5:
f1=
f2=
f3=
f4=
f5=
The optimal solution is:
(xsol,ysol)= (
Use this tab to check that this question works as expected.
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This question is used in the following exams: