Find the inverse of a composite function by finding the inverses of two functions and then the composite of these; and by finding the composite of two functions then finding the inverse. The question then concludes by asking students to compare their two answers and verify they're equivalent.

The student is asked to factorise a quadratic $x^2 + ax + b$. A custom marking script uses pattern matching to ensure that the student's answer is of the form $(x+a)(x+b)$, $(x+a)^2$, or $x(x+a)$.

To find the script, look in the Scripts tab of part a.

Students seem to freak out when their answer is not written exactly the same as the answer provided. This question tries to enforce that $(x-y)=-(y-x)$ and $\frac{a-b}{c-d}=\frac{b-a}{d-c}$

Students seem to freak out when their answer is not written exactly the same as the answer provided. This question tries to enforce that $(x-y)=-(y-x)$ and $\frac{a-b}{c-d}=\frac{b-a}{d-c}$

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Differentiate the function $f(x)=(a + b x)^m  e ^ {n x}$ using the product and chain rule. Find $g(x)$ such that $f^{\prime}(x)= (a + b x)^{m-1}  e ^ {n x}g(x)$. Non-calculator. Advice is given.

Differentiate the function $f(x)=(a + b x)^m  e ^ {n x}$ using the product and chain rule. Find $g(x)$ such that $f^{\prime}(x)= (a + b x)^{m-1}  e ^ {n x}g(x)$. Non-calculator. Advice is given.

This question shows how the number entry part marking algorithm has changed to award credit when the student gives the correct answer but to too much precision, when the precise value is not included in the rounded-off range of acceptable answers.

See this issue on GitHub.

Differentiate the function $f(x)=(a + b x)^m  e ^ {n x}$ using the product and chain rule. Find $g(x)$ such that $f^{\prime}(x)= (a + b x)^{m-1}  e ^ {n x}g(x)$. Non-calculator. Advice is given.

Simple procedures are given and student is asked to carry them out or un-do them.

Version 1: bi and bii have the same answer. biii and biv both have two answers.

Version 2: bi and bii have different answers. biii has two answers, biv has one answer.

Version 3: bi and bii have different answer. biii has one answer, biv has two answers.

Version 4: bi and bii have the same answer. biii has one answer, biv has two answers.

Simple procedures are given and student is asked to carry them out or un-do them.

Version 1: bi and bii have the same answer. biii and biv both have two answers.

Version 2: bi and bii have different answers. biii has two answers, biv has one answer.

Version 3: bi and bii have different answer. biii has one answer, biv has two answers.

Version 4: bi and bii have the same answer. biii has one answer, biv has two answers.

Simple procedures are given and student is asked to carry them out or un-do them.

Version 1: bi and bii have the same answer. biii and biv both have two answers.

Version 2: bi and bii have different answers. biii has two answers, biv has one answer.

Version 3: bi and bii have different answer. biii has one answer, biv has two answers.

Version 4: bi and bii have the same answer. biii has one answer, biv has two answers.

Simple procedures are given and student is asked to carry them out or un-do them.

Version 1: bi and bii have the same answer. biii and biv both have two answers.

Version 2: bi and bii have different answers. biii has two answers, biv has one answer.

Version 3: bi and bii have different answer. biii has one answer, biv has two answers.

Version 4: bi and bii have the same answer. biii has one answer, biv has two answers.

Simple procedures are given and student is asked to carry them out or un-do them.

Version 1: i and ii have the same answer. iii and iv both have two answers.

Version 2: i and ii have different answers. iii has two answers,biv has one answer.

Version 3: i and ii have different answer. iii has one answer, iv has two answers.

Version 4: i and ii have the same answer. iii has one answer, iv has two answers.

Simple procedures are given and student is asked to carry them out or un-do them.

Version 1: i and ii have the same answer. iii and iv both have two answers.

Version 2: i and ii have different answers. iii has two answers,biv has one answer.

Version 3: i and ii have different answer. iii has one answer, iv has two answers.

Version 4: i and ii have the same answer. iii has one answer, iv has two answers.

Simple procedures are given and student is asked to carry them out or un-do them.

Version 1: i and ii have the same answer. iii and iv both have two answers.

Version 2: i and ii have different answers. iii has two answers,biv has one answer.

Version 3: i and ii have different answer. iii has one answer, iv has two answers.

Version 4: i and ii have the same answer. iii has one answer, iv has two answers.

Simple procedures are given and student is asked to carry them out or un-do them.

Version 1: bi and bii have the same answer. biii and biv both have two answers.

Version 2: bi and bii have different answers. biii has two answers, biv has one answer.

Version 3: bi and bii have different answer. biii has one answer, biv has two answers.

Version 4: bi and bii have the same answer. biii has one answer, biv has two answers.

The thicknesses of two sedimentary layers are given. The student has to add the thicknesses and give the answer to 2 siginificant figures.

Differentiate the function $f(x)=(a + b x)^m  e ^ {n x}$ using the product and chain rule. Find $g(x)$ such that $f^{\prime}(x)= (a + b x)^{m-1}  e ^ {n x}g(x)$. Non-calculator. Advice is given.

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Inverse and division of complex numbers.  Four parts.

A set of MCQ designed to help Level 2 Engineering students prepare/practice for the on-line GOLA test that is used to assess the C&G 2850, Level 2 Engineering, Unit 202: Engineering Principles.

Multiplication and addition of complex numbers. Four parts.

Multiplication and addition of complex numbers. Four parts.

Multiplication and addition of complex numbers. Four parts.

No description given

A set of MCQ designed to help Level 2 Engineering students prepare/practice for the on-line GOLA test that is used to assess the C&G 2850, Level 2 Engineering, Unit 202: Engineering Principles.

Solve: $\displaystyle \frac{d^2y}{dx^2}+2a\frac{dy}{dx}+(a^2+b^2)y=0,\;y(0)=1$ and $y'(0)=c$. 

A set of MCQ designed to help Level 2 Engineering students prepare/practice for the on-line GOLA test that is used to assess the C&G 2850, Level 2 Engineering, Unit 202: Engineering Principles.