37 results.
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Question in Core Foundation Maths
Solve for x and y: a1x+b1y=c1a2x+b2y=c2
The included video describes a more direct method of solving when, for example, one of the equations gives a variable directly in terms of the other variable.
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Question in Skills Audits for Maths and Stats
Solving a pair of linear simultaneous equations, giving answers as integers or fractions.
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Question in MASH Bath: Question Bank
Solving a pair of linear simultaneous equations, giving answers as integers or fractions.
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Question in Chris's workspace
No description given
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Question in MASH Bath: Question Bank
Solving a pair of simultaneous equations of the form y=mx+c1 and y=ax2+kx+c2 to find the possible values for the unknown coefficient k, when given the values of m, a, c1 and c2.
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Question in Jos's workspace
Shows how to define variables to stop degenerate examples.
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Question in Jos's workspace
Solve for x and y: a1x+b1y=c1a2x+b2y=c2
The included video describes a more direct method of solving when, for example, one of the equations gives a variable directly in terms of the other variable.
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Question in Content created by Newcastle University by
Newcastle University Mathematics and Statistics
Solving three simultaneous congruences using the Chinese Remainder Theorem:
\begin{eqnarray*} x\;&\equiv&\;b_1\;&\mod&\;n_1\\ x\;&\equiv&\;b_2\;&\mod&\;n_2\\x\;&\equiv&\;b_3\;&\mod&\;n_3 \end{eqnarray*} where \operatorname{gcd}(n_1,n_2,n_3)=1
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Question in Content created by Newcastle University by
Newcastle University Mathematics and Statistics
Solving three simultaneous congruences using the Chinese Remainder Theorem:
\begin{eqnarray*} x\;&\equiv&\;b_1\;&\mod&\;n_1\\ x\;&\equiv&\;b_2\;&\mod&\;n_2\\x\;&\equiv&\;b_3\;&\mod&\;n_3 \end{eqnarray*} where \operatorname{gcd}(n_1,n_2,n_3)=1
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Question in Content created by Newcastle University by
Newcastle University Mathematics and Statistics
Solving two simultaneous congruences:
\begin{eqnarray*} c_1x\;&\equiv&\;b_1\;&\mod&\;n_1\\ c_2x\;&\equiv&\;b_2\;&\mod&\;n_2\\ \end{eqnarray*} where \operatorname{gcd}(c_1,n_1)=1,\;\operatorname{gcd}(c_2,n_2)=1,\;\operatorname{gcd}(n_1,n_2)=1
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Question in Content created by Newcastle University by
Newcastle University Mathematics and Statistics
Solving a pair of congruences of the form \begin{align}x &\equiv b_1\;\textrm{mod} \;n_1\\x &\equiv b_2\;\textrm{mod}\;n_2 \end{align} where n_1,\;n_2 are coprime.
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Question in Content created by Newcastle University by
Newcastle University Mathematics and Statistics
Solve for x and y: \begin{eqnarray} a_1x+b_1y&=&c_1\\ a_2x+b_2y&=&c_2 \end{eqnarray}
The included video describes a more direct method of solving when, for example, one of the equations gives a variable directly in terms of the other variable.
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Question in Content created by Newcastle University by
Newcastle University Mathematics and Statistics
Solve for x and y: \begin{eqnarray} a_1x+b_1y&=&c_1\\ a_2x+b_2y&=&c_2 \end{eqnarray}
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Question in Transition to university
This question tests the student's ability to solve simple linear equations by elimination. Part a) involves only having to manipulate one equation in order to solve, and part b) involves having to manipulate both equations in order to solve.
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Simultaneous Equations
rebelmaths
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Word Problems leading to simultaneous Linear Equations
rebelmaths
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Question in Algebra
Shows how to define variables to stop degenerate examples.
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Question in Algebra
Solving simple simultaneous equations.
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Question in Rob's workspace
No description given
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Three items of work done on a car. Given total price, and a couple of ratios of prices between pairs of items, work out the cost of one of the items.
Based on question 4 from section 3 of the Maths-Aid workbook on numerical reasoning.
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Question in vijay's workspace
Find the coordinates of the stationary point for f: D \rightarrow \mathbb{R}: f(x,y) = a + be^{-(x-c)^2-(y-d)^2}, D is a disk centre (c,d).
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Question in Bill's workspace
Solve for x and y: \begin{eqnarray} a_1x+b_1y&=&c_1\\ a_2x+b_2y&=&c_2 \end{eqnarray}
The included video describes a more direct method of solving when, for example, one of the equations gives a variable directly in terms of the other variable.
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Question in Bill's workspace
Shows how to define variables to stop degenerate examples.
